Answer:
y($) = 405- 20x
Step-by-step explanation:
Number of short driveways = x
Number of long driveways = 9-x
Fee per long driveway = $45
Fee per short driveway= $25
Total amount = y
y ($) = 25x + 45 (9-x)
= 25x + 405 -45x
= 405- 20x
Answer:
A
Step-by-step explanation:
The price of jacket was $24.54
Step-by-step explanation:
Let,
Cost of jacket = x
Cost of pair of shoes = y
According to given statement;
x+y=52.95 Eqn 1
x = y-3.87 Eqn 2
Putting value of x from Eqn 2 in Eqn 1

Dividing both sides by 2

Putting y=28.41 in Eqn 2,

The price of jacket was $24.54
Keywords: linear equation, division
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Answer:
i think the awnser is c . if unattended, leave the horse tire up
General Idea:
Domain of a function means the values of x which will give a DEFINED output for the function.
Applying the concept:
Given that the x represent the time in seconds, f(x) represent the height of food packet.
Time cannot be a negative value, so

The height of the food packet cannot be a negative value, so

We need to replace
for f(x) in the above inequality to find the domain.
![-15x^2+6000\geq 0 \; \; [Divide \; by\; -15\; on\; both\; sides]\\ \\ \frac{-15x^2}{-15} +\frac{6000}{-15} \leq \frac{0}{-15} \\ \\ x^2-400\leq 0\;[Factoring\;on\;left\;side]\\ \\ (x+200)(x-200)\leq 0](https://tex.z-dn.net/?f=%20-15x%5E2%2B6000%5Cgeq%200%20%5C%3B%20%5C%3B%20%20%5BDivide%20%5C%3B%20by%5C%3B%20-15%5C%3B%20on%5C%3B%20both%5C%3B%20sides%5D%5C%5C%20%5C%5C%20%5Cfrac%7B-15x%5E2%7D%7B-15%7D%20%2B%5Cfrac%7B6000%7D%7B-15%7D%20%5Cleq%20%5Cfrac%7B0%7D%7B-15%7D%20%5C%5C%20%5C%5C%20x%5E2-400%5Cleq%200%5C%3B%5BFactoring%5C%3Bon%5C%3Bleft%5C%3Bside%5D%5C%5C%20%5C%5C%20%28x%2B200%29%28x-200%29%5Cleq%200%20)
The possible solutions of the above inequality are given by the intervals
. We need to pick test point from each possible solution interval and check whether that test point make the inequality
true. Only the test point from the solution interval [-200, 200] make the inequality true.
The values of x which will make the above inequality TRUE is 
But we already know x should be positive, because time cannot be negative.
Conclusion:
Domain of the given function is 