Here is the answer to your problem
They are essentially asking us to solve:
Solving this equation for x tells us that it will take around 80.1 years for the materials in the vault to reduce to 357 pounds.
...6 and 10 are roots, so x – 6 and x – 10 are factors.
y = a(x – 6)(x – 10).....plug in the point (8, 2) and solve for a:
2 = a(8 – 6)(8 – 10)
2 = –4a
a = –1/2
...y = (–1/2)(x – 6)(x – 10)
...y = (–1/2)(x² – 16x + 60)
...y = (–x²/2) + 8x – 30 <<<------Answer, or:
...y = (–1/2)(x – 8)² + 2 <<<------Answer
This question is incomplete
Complete Question
An arts academy requires there to be 6 teachers for every 132 students and 4 tutors for every 44 students. How many students does the academy have per teacher? Per tutor? How many tutors does the academy need if it has 132 students?
Answer:
a)How many students does the academy have per teacher?
22 students per teacher
b) Per tutor?
11 students per tutor
c) How many tutors does the academy need if it has 132 students?
12 tutors
Step-by-step explanation:
a)How many students does the academy have per teacher?
6 teachers = 132 students
1 teacher = x
6 × x = 132 × 1
x = 132 × 1/6
x = 22 students
Hence, we have 22 students per tutor
b) Per tutor?
4 tutors = 44 students
1 tutor = x students
Cross Multiply
4 × x = 1 × 44
x = 44/4
x = 11 students
Hence, we have 11 students per tutor
c) How many tutors does the academy need if it has 132 students?
44 students = 4 tutors
132 students = x tutors
Cross Multiply
44 × x = 132 × 4
44x = 132 × 4
x = 132 × 4/44
x = 12 tutors
The academy needs 12 tutors if they have 132 students.
It’s A!!!! 3:2 hope i helped
