A triangle has squares on its three sides as shown below. What is the value of x? (1 point) x cm 3 cm 4 cm 1) 3 centimeters O2)
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Answer:
The root of the equation is x ≈ 0.162035
Step-by-step explanation:
To find the roots of the equation you can use the Newton-Raphson method.
It is a way to find a good approximation for the root of a real-valued function f(x) = 0. The method starts with a function f(x) defined over the real numbers, the function derivative f', and an initial guess for a root of the function. It uses the idea that a continuous and differentiable function can be approximated by a straight line tangent to it.
This is the expression that we need to use
For the information given:
For the initial value you can choose
although you can choose any value that you want.
So for approximation
Next, with you put it into the equation
, you can see that this value is close to 0 but we need to refine our solution.
For approximation
Again we put into the equation
this value is close to 0 but again we need to refine our solution.
We can summarize this process in the following table.
The approximation gives you the root of the equation.
When you plot the equation you find that only have one real root and is approximate to the value found.
The value of the given statement according to the mid point theorem is 5.
According to the statement
we have given that the equation and we have to integrate it with the help of the mid point theorem.
So, For this purpose, we know that the
The midpoint theorem states that “The line segment in a triangle joining the midpoint of two sides of the triangle is said to be parallel to its third side and is also half of the length of the third side.”
So, The given equation is
where n = 4
And
The mid point formula is a with limits a to b is
f(x) dx ≈ Δx (f (x₀ + x₁)/2) + (f (x₁ + x₂)/2) + ... (f (xₓ₋₂ + xₓ₋₁)/2) + (f (xₓ₋₁ + x)/2))
Then
Where Δx = (b-a)/n
Recall that
a= 0
b= 64 and
n=4, therefore,
Δx = (64-0)/4 = 16
The next step requires that the interval [0,64] be divided into 4 sub-intervals with length = Δx =16
Hence, we've got, 0, 16, 32, 48, 64.
From this point, we calibrate the respective functions as follows:
f (x₀ + x₁)/2) = f ((0+16)/2) = f(8) = Sin (8) = 0.98935824662
(f (x₁ + x₂)/2) = f((16+32)/2) = f(24) =Sin (24) = -0.905578362
(f (x₂ + x₃)/2) = f((32+48)/2) = f(40) = Sin (40) = 0.74511316047
(f (x₃ + x₄)/2) = f((48+64)/2) = f(56) = Sin (56) = -0.52155100208
At this point, we sum up the above values derive the product of the total and Δx = 16
sin (x) dx = 16(0.98935824662 - 0.905578362 + 0.74511316047 - 0.52155100208)
= 16 (0.30734204301)
= 4.91747268816
So, The value of the given statement according to the mid point theorem is 5.
Learn more about Mid point theorem here
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