There are 2 electrons generated from the oxidation of one water molecule.
<h3>Describe photooxidation.</h3>
The process of a substance interacting with oxygen or losing electrons from chemical species under the influence of light is known as photooxidation. Photooxidation happens in plants when there is environmental stress. It is called photooxidative stress as a result. Reactive oxygen species are produced by the absorption of excess excitation energy in plant tissues. Chloroplasts are harmed by the accumulation of these reactive oxygen species, which is a damaging process in plants. High-intensity light and little
are the two conditions that cause this photooxidative stress to occur most frequently. It is a procedure that requires light. Photorespiration in
plants guards against photooxidation.
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1. its must be B and 2. must be C
Answer:
Total impulse =
= Initial momentum of the car
Explanation:
Let the mass of the car be 'm' kg moving with a velocity 'v' m/s.
The final velocity of the car is 0 m/s as it is brought to rest.
Impulse is equal to the product of constant force applied to an object for a very small interval. Impulse is also calculated as the total change in the linear momentum of an object during the given time interval.
The magnitude of impulse is the absolute value of the change in momentum.

Momentum of an object is equal to the product of its mass and velocity.
So, the initial momentum of the car is given as:

The final momentum of the car is given as:

Therefore, the impulse is given as:

Hence, the magnitude of the impulse applied to the car to bring it to rest is equal to the initial momentum of the car.
Answer:
q = 0.036 C
Explanation:
Given that,
Current passes through a defibrillator, I = 18 A
Time, t = 2 ms
We need to find the charge moved during this time. We know that,
Electric current = charge/time

Put all the values,

So, 0.036 C of charge moves during this time.
Answer:
0.015
Explanation:
Total volume of water coming out = 1.33
Also volume = Cross sectional area*Length covered
Length covered = Velocity *time
=24.5*3.55
=86.97 meter
Let the cross sectional area be A.
1.33 = 86.97*A
A =0.015