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Ira Lisetskai [31]
3 years ago
10

What is one advantage of using a computer over a graphing calculator?

Physics
2 answers:
Elena L [17]3 years ago
6 0
When you are on a computer there are sites like Google and Bing , and they can help you with over 9.9 billion answers and solutions they also have sites like Brainly....   :) which are a big help. we show you steps and many solutions and options.

A calculator just gives you the answer and nothing more.  If your lucky you will type in something that has no answer.

so a computer is better. , I hope this helps you :)
Dahasolnce [82]3 years ago
4 0
A computer can show you how it is done and how they got to that solution while a graphing calculator can only show you the solution. 
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tino4ka555 [31]
1.791MN is the answer
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3 years ago
What is Particle-antiparticle annihilation after watching the video minutephysics Antimatter Explained
LenKa [72]

Answer:

Particle-antiparticle annihilation is the result of a direct interaction between a particle and its corresponding anti particle, like a proton and an anti-proton or an electron and a positron. The result of such interaction is the production of two powerful gamma rays, each of whom has an energy roughly equal to E = mc^2, where m is the mass of the particle.

3 0
3 years ago
A standard gold bar stored at Fort Knox, Kentucky, is 7.00 inches long, 3.63 inches wide, and 1.75 inches tall. Gold has a densi
Liula [17]

Answer:

14.1 kg

Explanation:

Given:

Length=7.00inches

Width=3.63 inches

Height=1.75 inches

density = 19,300 kg/m3.

We can convert the given parameters to metre for unit consistency

But we know 1 inches= 0.0254 metre

✓Then Length l=7.00inches

=7×0.0254 metre=0.1778m

✓Width w =3.63 inches

==3.63 ×0.0254 metre=0.092m

✓Height h =1.75 inches

=1.75 ×0.0254 metre=0.0445 m

But Mass= density × volume

Volume= Length× width×height

Mass= density× Length× width×height

= 19300kg/m³×0.1778×0.0922×0.0445

=14.1 kg

Therefore, the mass of the gold bar is 14.1 kg

4 0
3 years ago
A cannon is fired straight up into the air. If the cannon ball comes back down to the launch point in 5 seconds, what was the ma
Nana76 [90]

Answer:

30.63 m

Explanation:

From the question given above, the following data were obtained:

Total time (T) spent by the ball in air = 5 s

Maximum height (h) =.?

Next, we shall determine the time taken to reach the maximum height. This can be obtained as follow:

Total time (T) spent by the ball in air = 5 s

Time (t) taken to reach the maximum height =.?

T = 2t

5 = 2t

Divide both side by 2

t = 5/2

t = 2.5 s

Thus, the time (t) taken to reach the maximum height is 2.5 s

Finally, we shall determine the maximum height reached by the ball as follow:

Time (t) taken to reach the maximum height = 2.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) =.?

h = ½gt²

h = ½ × 9.8 × 2.5²

h = 4.9 × 6.25

h = 30.625 ≈ 30.63 m

Therefore, the maximum height reached by the cannon ball is 30.63 m

3 0
4 years ago
A particle begins to move with uniform acceleration. If in the first second it travels 3m
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Answer:6m

Explanation:

8 0
3 years ago
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