The momentum of the ball when it hits the ground is 4.89 kg.m/s.
The given parameters;
- <em>mass of the baseball, m = 0.145 kg</em>
- <em>height of fall of the ball, h = 58 m</em>
The final velocity of the ball when it hits the ground is calculated as follows;
The momentum of the ball when it hits the ground is calculated as follows;
P = mv
P = 0.145 x 33.72
P = 4.89 kg.m/s
Thus, the momentum of the ball when it hits the ground is 4.89 kg.m/s.
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Answer:
hey u apply p=mv and 2 are given then calculate thirds value it's a simple do it
The work done onto the car is 506,250 J
The work done on a system implies an increase in the internal energy of the system as a result of some forces acting on the system from the outside.
From the parameters given:
- The mass of the car = 1500 kg
- The initial speed = 30 m/s
- The final speed = 15 m/s
The work done onto the car refers to the change in the kinetic energy (i.e. ΔK.E)
= 506,250 J
Therefore, we can conclude that the work done on the car is 506,250 J
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Answer:
creo que es la opcion numero 4.
F = (mass)(acceleration) = ma
m = 0.2 kg
Vi = 32 m/s
t = 0.5 s
Vf = 0 m/s (since it was put to stop)
a=(Vf-Vi)/t
a=(0-32)/0.5
a = 64 m/s^2 (decelerating)
F = ma = (0.2 kg)(64 m/s^2)
F = 12.8 N
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this answer will be a good h<span>elp for you.</span></span>
