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JulijaS [17]
3 years ago
14

Whats is your name boy and girl

Physics
2 answers:
azamat3 years ago
7 0

Answer:

lol what.

Explanation:

Verizon [17]3 years ago
3 0

Answer:

i am named after my dad

Explanation:

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A substance maintaining a uniform appearence throught is called
BabaBlast [244]
A substance maintaining a uniform appearance throught is called homogeneous
6 0
4 years ago
Katelyn (55 kg) is practicing a drop jump in the biomechanics lab. She steps off a plyometrics box, lands on the force plate, an
suter [353]

Answer:

J = 357.5 kg*m/s

Explanation:

  • The impulse exerted on Katelyn when she was on the force plate, is equal to the change in her momentum, according to Newton's 2nd Law.
  • Assuming as the positive direction the upward direction (coincident with the positive y-axis) we can express the initial momentum as follows:

       p_{o} = m*v_{o} = 55 kg * (-3.0 m/s)  (1)

  • By the same token, the final momentum is as follows:

       p_{f} = m*v_{f} = 55 kg * (3.5 m/s)  (2)

  • As we have already said, the impulse J is just equal to the change in momentum, i.e., the difference between (2) and (1):

      J = p_{f} - p_{o} = m* (v_{f} -v_{o}) = 55 kg* (3.5m/s- (-3.0m/s)) = 357.5 kg*m/s (3)

5 0
3 years ago
What is the force in N of an object that has a mass of 7 kilograms and acceleration of 6 m/s/s
Marina86 [1]

Newton's 2nd law of motion:         Force = (mass) x (acceleration)

If you want to move a 7-kg object with an acceleration of 6 m/s²,
then you will need to push it with (7 x 6) = 42 newtons of force.

You don't mean the force of an object.

4 0
3 years ago
Can someone explain this to me? 20 POINTS!
Anarel [89]

Answer:What is the first law of thermodynamics and how does it relate to energy use? The first law of thermodynamics states that energy is conserved in chemical processes. ... This amount of energy that must be lost to the surroundings for the process to occur is nature's heat tax, an unavoidable cut of every energy transaction.

Explanation:

3 0
3 years ago
A particle's position along the x-axis is described by. x(t)= At+Bt^2where t is In seconds: x is in meters: and the constants A
DanielleElmas [232]

Answer

given,

position of particle

x(t)= A t + B t²

A = -3.5 m/s

B = 3.9 m/s²

t = 3 s

a)  x(t)= -3.5 t + 3.9 t²

   velocity of the particle is equal to the differentiation of position w.r.t. time.

\dfrac{dx}{dt}=\dfrac{d}{dt}(-3.5t + 3.9t^2)

v= -3.5 + 7.8 t------(1)

velocity of the particle at t = 3 s

  v = -3.5 + 7.8 x 3

 v = 19.9 m/s

b) velocity of the particle at origin

  time at which particle is at origin

  x(t)= -3.5 t + 3.9 t²

   0 = t (-3.5  + 3.9 t )

   t = 0, t=\dfrac{3.5}{3.9}

   t = 0 , 0.897 s

speed of the particle at t = 0.897 s

from equation (1)

 v = -3.9 + 7.8 t

 v = -3.9 + 7.8 x 0.897

  v = 3.1 m/s

6 0
4 years ago
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