Cabs charge $3.60 Flag Fall plus $2.19 per km. (a) Write down an equation to calculate the cost, C, of cab fare for a distance d
1 answer:
(a) C = 3.60+2.19d
(b) The cab fare will be $36.45 for a distance of d kilometers.
Step-by-step explanation:
Given,
Charges of Flag Fall = $3.60
Per kilometer charges = $2.19
Let,
d be the total distance.
C be the total cost for d kilometers.
(a) Write down an equation to calculate the cost, C, of cab fare for a distance d kilometres.
Total cost = Charges of flag fall + Per kilometer charges * distance
C = 3.60+2.19d
(b) Use your equation to calculate the cost of cab fare for a distance of 15 km.
Here,
d=15
Putting in Equation
The cab fare will be $36.45 for a distance of d kilometers.
Keywords: distance, addition
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Answer:
The missing statement is ∠ACB ≅ ∠ECD
Step-by-step explanation:
Given two lines segment AC and BD bisect each other at C.
We have to prove that ΔACB ≅ ΔECD
In triangle ACB and ECD
AC=CE (Given)
BC=CD (Given)
Now to prove above two triangles congruent we need one more side or angle
so, as seen in options the angle ∠ACB ≅ ∠ECD due to vertically opposite angles
hence, the missing statement is ∠ACB ≅ ∠ECD
