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cestrela7 [59]
2 years ago
6

Match the words in the left-hand column to the appropriate blank in the sentences in the right-hand column. Use each word only o

nce.
1. Nuclear fusion of hydrogen into helium occurs in the_______ .
2. Energy moves through the Sun's ________ by means of the rising of hot gas and falling of cooler gas.
3. Nearly all the visible light we see from the Sun is emitted from the_______ .
4. Most of the Sun's ultraviolet light is emitted from the narrow layer called the _______where temperature increases with altitude.
5. We can see the Sun's _______ most easily during total solar eclipses.
6. The _______ is the layer of the Sun between its core and convection zone.
Physics
1 answer:
Schach [20]2 years ago
4 0

The answer to the question are bulleted below

  1. <em>Core</em>
  2. <em>Convection Zone</em>
  3. <em>Photosphere</em>
  4. <em>Chromosphere</em>
  5. <em>Corona</em>
  6. <em>Radiation Zone</em>

1. Nuclear fusion of hydrogen into helium occurs in the core.

2. Energy moves through the Sun's Convection Zone by means of the rising of hot gas and falling of cooler gas.

3. Nearly all the visible light we see from the Sun is emitted from the <u>Photosphere.</u>

4. Most of the Sun's ultraviolet light is emitted from the narrow layer called the Chromosphere where temperature increases with altitude.

5. We can see the Sun's Corona most easily during total solar eclipses.

6. The <u>Radiation Zone</u> is the layer of the Sun between its core and convection zone.

see more here  brainly.com/question/18767319

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A 2800 kg truck moving at 12 m/s to the right hits a stopped 1100 kg car. What is the combined velocity the moment they stick to
leva [86]

Answer:

The combined velocity is 8.61 m/s.

Explanation:

Given that,

The mass of a truck, m = 2800 kg

Initial speed of truck, u = 12 m/s

The mass of a car, m' = 1100 kg

Initial speed of the car, u' = 0

We need to find the combined velocity the moment they stick together. Let it is V. Using the conservation of momentum.

m_1v_1+m_2v_2=(m_1+m_2)V\\\\V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}\\\\V=\dfrac{2800\times 12+0}{2800+1100}\\\\V=8.61\ m/s

So, the combined velocity is 8.61 m/s.

5 0
3 years ago
What is the relationship between frequency ad wavelenght
Law Incorporation [45]

Answer:

Frequency and wavelength are inversely proportional to each other. The wave with the greatest frequency has the shortest wavelength. Twice the frequency means one-half the wavelength. For this reason, the wavelength ratio is the inverse of the frequency ratio.

7 0
3 years ago
Read 2 more answers
Match each term to its definition.
den301095 [7]
Answer: first one is electrochemical
Second one is combustion
Third one is photosynthesis
Fourth one is respiration
8 0
3 years ago
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Froghopper insects have a typical mass of around 11.3 mg and can jump to a height of 58.8 cm. The takeoff velocity is achieved a
allochka39001 [22]

Answer:

2874.33 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s²

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{v^2-0^2}{2\times h}\\\Rightarrow v^2=2ah\ m/s

Now H-h = 0.588 - 0.002 = 0.586 m

The final velocity will be the initial velocity

v^2-u^2=2as\\\Rightarrow 0^2-u^2=2gs\\\Rightarrow -2ah=2\times g(H-h)\\\Rightarrow -2a0.002=2\times g0.586\\\Rightarrow a=-\frac{0.586\times -9.81}{0.002}\\\Rightarrow a=2874.33\ m/s^2

Acceleration of the frog is 2874.33 m/s²

6 0
3 years ago
A force of 60 N is applied to a skier to pull him along a horizontal surface so that his speed remains constant. If the coeffici
matrenka [14]

Answer:

1200\ \text{N}

Explanation:

F = Force on the skier = 60 N

\mu = Coefficient of friction = 0.05

w = Weight of skier

Force is given by

F=\mu w

\Rightarrow w=\dfrac{F}{\mu}

\Rightarrow w=\dfrac{60}{0.05}=\dfrac{6000}{5}

\Rightarrow w=1200\ \text{N}

Weight of the skier on which the force is being applied is 1200\ \text{N} .

7 0
3 years ago
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