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cestrela7 [59]
2 years ago
6

Match the words in the left-hand column to the appropriate blank in the sentences in the right-hand column. Use each word only o

nce.
1. Nuclear fusion of hydrogen into helium occurs in the_______ .
2. Energy moves through the Sun's ________ by means of the rising of hot gas and falling of cooler gas.
3. Nearly all the visible light we see from the Sun is emitted from the_______ .
4. Most of the Sun's ultraviolet light is emitted from the narrow layer called the _______where temperature increases with altitude.
5. We can see the Sun's _______ most easily during total solar eclipses.
6. The _______ is the layer of the Sun between its core and convection zone.
Physics
1 answer:
Schach [20]2 years ago
4 0

The answer to the question are bulleted below

  1. <em>Core</em>
  2. <em>Convection Zone</em>
  3. <em>Photosphere</em>
  4. <em>Chromosphere</em>
  5. <em>Corona</em>
  6. <em>Radiation Zone</em>

1. Nuclear fusion of hydrogen into helium occurs in the core.

2. Energy moves through the Sun's Convection Zone by means of the rising of hot gas and falling of cooler gas.

3. Nearly all the visible light we see from the Sun is emitted from the <u>Photosphere.</u>

4. Most of the Sun's ultraviolet light is emitted from the narrow layer called the Chromosphere where temperature increases with altitude.

5. We can see the Sun's Corona most easily during total solar eclipses.

6. The <u>Radiation Zone</u> is the layer of the Sun between its core and convection zone.

see more here  brainly.com/question/18767319

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A 30-mm-diameter copper rod is 1 m long with a yield strength of 70 MPa. Determine the axial force necessary to cause the diamet
ivolga24 [154]

Explanation:

Given data:

d = 30 mm = 0.03 m

L = 1m

S_{y} = 70 Mpa

Δd = -0.0001d

Axial force = ?

validity of elastic deformation assumption.

Solution:

O'₂ = Δd/d = (-0.0001d)/d = -0.0001

For copper,

v = 0.326      E = 119×10³ Mpa

O'₁ = O'₂/v = (-0.0001)/0.326 = 306×10⁶

∵δ = F.L/E.A    and σ = F/A so,

σ = δ.E/L = O'₁ .E = (306×10⁻⁶).(119×10³) = 36.5 MPa

F = σ . A = (36.5 × 10⁻⁶) . (π/4 × (0.03)²) = 25800 KN

S_{y} = 70 MPa > σ = 36.5 MPa

∵ elastic deformation assumption is valid.

so the answer is

F = 25800 K N            and     S_{y} > σ

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