Answer:
The angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is <u>10°.</u>
Explanation:
Given:
Mass of the driver is, ![m=55\ kg](https://tex.z-dn.net/?f=m%3D55%5C%20kg)
Radius of circular turn is, ![R=300\ m](https://tex.z-dn.net/?f=R%3D300%5C%20m)
Linear speed of the car is, ![v=22.2\ m/s](https://tex.z-dn.net/?f=v%3D22.2%5C%20m%2Fs)
Since, the car makes a circular turn, the driver experiences a centripetal force radially inward towards the center of the circular turn. Also, the driver experiences a downward force due to her weight. Therefore, two forces act on the driver which are at right angles to each other.
The forces are:
1. Weight = ![mg=55\times 9.8=539\ N](https://tex.z-dn.net/?f=mg%3D55%5Ctimes%209.8%3D539%5C%20N)
2. Centripetal force, 'F', which is given as:
![F=\frac{mv^2}{R}\\F=\frac{55\times (22.2)^2}{300}\\\\F=\frac{55\times 492.84}{300}\\\\F=\frac{27106.2}{300}=90.354\ N](https://tex.z-dn.net/?f=F%3D%5Cfrac%7Bmv%5E2%7D%7BR%7D%5C%5CF%3D%5Cfrac%7B55%5Ctimes%20%2822.2%29%5E2%7D%7B300%7D%5C%5C%5C%5CF%3D%5Cfrac%7B55%5Ctimes%20492.84%7D%7B300%7D%5C%5C%5C%5CF%3D%5Cfrac%7B27106.2%7D%7B300%7D%3D90.354%5C%20N)
Now, the angle of the net force acting on the driver with respect to the vertical is given by the tan ratio of the centripetal force (Horizontal force) and the weight (Vertical force) and is shown in the triangle below. Thus,
°
Therefore, the angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is 10°.
D !.!.!.!.!.!!.!.!.!.!.!.!.!.!.!.!.!.!.!.!.!.!.!!..!!..!
Answer:
The radius is ![r = 3.1905 \ m](https://tex.z-dn.net/?f=r%20%3D%203.1905%20%5C%20m)
Explanation:
From the question we are told that
The distance beneath the liquid is ![d = 2.70 \ m](https://tex.z-dn.net/?f=d%20%3D%20%202.70%20%5C%20m)
The refractive index of the liquid is ![n_i = 1.31](https://tex.z-dn.net/?f=n_i%20%20%3D%20%201.31)
Now the critical value is mathematically represented as
![\theta = sin ^{-1} [\frac{1}{n_i} ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20sin%20%5E%7B-1%7D%20%5B%5Cfrac%7B1%7D%7Bn_i%7D%20%5D)
substituting values
![\theta = sin ^{-1} [\frac{1}{131} ]](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20%20sin%20%5E%7B-1%7D%20%5B%5Cfrac%7B1%7D%7B131%7D%20%5D)
![\theta = 49.76^o](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%2049.76%5Eo)
Using SOHCAHTOA rule we have that
![tan \theta = \frac{ r}{d}](https://tex.z-dn.net/?f=tan%20%5Ctheta%20%3D%20%20%5Cfrac%7B%20r%7D%7Bd%7D)
=> ![r = d * tan \theta](https://tex.z-dn.net/?f=r%20%3D%20%20d%20%2A%20tan%20%5Ctheta)
substituting values
![r = 2.7 * tan (49.76)](https://tex.z-dn.net/?f=r%20%3D%20%202.7%20%2A%20tan%20%2849.76%29)
![r = 3.1905 \ m](https://tex.z-dn.net/?f=r%20%3D%203.1905%20%5C%20m)
The answer to this question would be: <span>A) animals that live in deserts
</span>Desert temperature is high, especially in the day, <span>An animal that lives in the desert needs to adapt to the high temperature either by reducing the heat or by increasing heat loss. By becoming nocturnal, the animal also able to evade the sunlight so it was less exposed to the heat.
Unlike other option, the desert is lacking water. Desert is mostly dry and water would be a resource that hard to find. In this case, k</span><span>idneys adapted to check water loss would be a great help</span>