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3 years ago

(3,-5) and (3,-9) slope intercept form

Mathematics

1 answer:

user100 [1]3 years ago

7 0

Answer:

Step-by-step explanation:

To find the slope intercept form you need to use the formula:

$\frac{y_2-y_1}{x_2-x_1} =slope$

(3,-5)(3,-9)

(x1,y1)(x2,y2)

$\frac{-9-(-5)}{3-3} =\frac{-9+5}{0}=\frac{-4}{0}=0$

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Dmitrij [34]

Answer:

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3 years ago

Jay is letting her bread dough rise. After three hours, her bread dough is \dfrac{11}{5} 5 11 start fraction, 11, divided by,

timama [110]

Answer:

Jay's bread size is 220% of the original size.

Step-by-step explanation:

The question is incomplete.

The complete question is as follows.

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Solution:

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3 years ago

I need help with number 19

inysia [295]

Let's start by understanding that the graph is a linear line. We have a common difference if 4.5 for every 10x we have more.

We can start by finding the gradient, using rise over run. Let's take (10, 4.5) and (20, 9)

Our rise is 9 - 4.5 = 4.5 and our run is 10. Then, our gradient becomes 4.5/10 = 0.45

Now, we can substitute points using the point-slope form.

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Hence, our line becomes y = 0.45x and you can verify by substituting in points from the table.

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3 years ago

F(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, ∞) and g(x) = 2x2 + 8x + 6,

svetlana [45]

Answer:

B) Both functions have the same domain.

C) Both functions have the same x-intercepts.

D) Both functions are decreasing on the interval (−∞, −2).

Step-by-step explanation:

step 1

Find the vertex of f(x)

we know that

The x-coordinate of the vertex is the midpoint of the roots

we have

x=-1 and x=-3

the midpoint is

(-1-3)/2=-2

The y-coordinate of the vertex is -4 (because the range is [−4, ∞))

therefore

The vertex of f(x) is the point (-2,-4)

Is a vertical parabola open upward

The vertex is a minimum

The domain is all real numbers

step 2

we have

$g(x)=2x^2+8x+6$

Find the vertex

Factor the leading coefficient

$g(x)=2(x^2+4x)+6$

Complete the square

$g(x)=2(x^2+4x+4)+6-8$

$g(x)=2(x^2+4x+4)-2$

Rewrite as perfect squares

$g(x)=2(x+2)^2-2$

Is a vertical parabola open upward

The vertex is the point (-2,-2)

The domain is all real numbers

The range is the interval [−2, ∞)

Find the x-intercepts

For g(x)=0

$0=2(x+2)^2-2$

$2(x+2)^2=2$

$(x+2)^2=1\\x+2=\pm1\\x=-2\pm1$

The roots or x-intercepts are

x=-1 and x=-3

<u><em>Verify each statement</em></u>

A) Both functions have the same vertex

The statement is false

The vertex of f(x) is (-2,-4) and the vertex of g(x) is (-2,-2)

B) Both functions have the same domain.

The statement is true

The domain is all real numbers

C) Both functions have the same x-intercepts

The statement is true (see the explanation)

D) Both functions are decreasing on the interval (−∞, −2)

The statement is true

Because the x-coordinate of the vertex is the same in both functions, and both functions open upward

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(3,-5) and (3,-9) slope intercept form​

(3,-5) and (3,-9) slope intercept form