Answer:
18.62 m/s
Explanation:
Given that:
A liquid with a density of 900 kg/m 3 is stored in a pressurized, closed storage tank.
Diameter of the tank = 10 m
The absolute pressure in the tank above the liquid is 200 kPa = 200, 000 Pa
At pressure of 200 kPa ; the final velocity = 0
Atmospheric pressure at 5cm = 101325 Pa
We are to calculate the initial velocity of a fluid jet when a 5cm diameter orifice is opened at point A?
By using Bernoulli's theorem between the shaded portion in the diagram;
we have:




where;
Pa = atmospheric pressure = 101325 Pa
= density of liquid = 900 kg/m³
= initial velocity = ???
g = 9.8 m/s²
= height of the hole from the buttom
= height of the liquid surface from the button


Thus, the initial velocity of the fluid jet = 18.62 m/s
Answer:position relative to the starting point
Explanation:
Answer:
The rotor's angular velocity is 82.73rad/s
Explanation:
It is a curvilinear movement of a constant radius. If there is uniform angular acceleration, then it is a circular motion with constant acceleration, whose equations are analogous to that of the translational motion.
Calculating the initial velocity of the rotor, V1 in rad/s
V1 = 610rev/minute × 6.28 × 1miute/60secs
V1 = 63.85rad/s
Using kinematic equation to calculate the final velocity of the rotor
Given:
Angular acceleration = 5.9rad/s^2
Time,t= 3.2seconds
V2 = V1 + a × t
V2 = 63.85 + (5.9)× (3.2)
V2 = 63.85 + 18.88
V2 = 82.73rads/s
1) The electrostatic force between the two pieces of paper is 
2)
- If the charges of the two pieces of paper are both + or both -, they repel each other
- If the charges of one piece of paper is positive and the other one is negative, they attract each other
Explanation:
1)
The electrostatic force between two charged objects is given by Coulomb's law:

where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
In this problem, we have the following situation:
is the charge on the first piece of paper
is the charge on the second piece of paper
is their separation
Substituting into the equation, we find the magnitude of the electrostatic force between them:

2)
The electrostatic force can be either attractive of repulsive, depending on the relative sign of the charges of the objects involved.
In particular, we have:
- If the two charges have same sign (both positive or both negative), the force between them is repulsive
- If the two charges have opposite sign (one positive and one negative), the force between them is attractive
Therefore, in this case:
- If the charges of the two pieces of paper are both + or both -, they repel each other
- If the charges of one piece of paper is positive and the other one is negative, they attract each other
Learn more about electric force:
brainly.com/question/8960054
brainly.com/question/4273177
#LearnwithBrainly
Answer:
n = 1.76
Explanation:
According to the rule of ( n1 sin theta1 = n2 sin theta2 )
we know both angles so we insert them to the law and apply n1 = 1
so 1/2 = n2 sin 62 and we get the final answer