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DaniilM [7]
3 years ago
13

Joey has 39 pieces of candy if Sally asked joey for 5 pieces, Sam ask for 10, and John ask for 6, but sally got 4 more than Sam.

how many pieces does Joey have left?
Mathematics
1 answer:
julsineya [31]3 years ago
5 0

Answer:he should only have 9 pieces left

Step-by-step explanation:

You are subtracting 14,10,and 6 which equals 30 from 39. Since Sally got 4 more than Sam she got 14 instead of 5

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LeRoy, a starting player for a major college basketball team, made only 40% of his free throws last season. During the summer, h
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Answer:

z=\frac{0.625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{40}}}=2.905  

p_v =P(z>2.905)=0.0018  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of free throws made is higher than 0.4

Step-by-step explanation:

Data given and notation

n=40 represent the random sample taken

X=25 represent the number of free throws made

\hat p=\frac{25}{40}=0.625 estimated proportion of free throws made

p_o=0.4 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.4:  

Null hypothesis:p\leq 0.4  

Alternative hypothesis:p > 0.4  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.625 -0.4}{\sqrt{\frac{0.4(1-0.4)}{40}}}=2.905  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.905)=0.0018  

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