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lina2011 [118]
3 years ago
14

If a rectangle has side lengths x+4 and 2x what is the perimeter and area of the rectangle?

Mathematics
1 answer:
pochemuha3 years ago
7 0

Answer:

Perimeter: 6x+8

Area: 2x²+8x

Step-by-step explanation:

Perimeter- the sum of all sides

So, you do x+4+x+4+2x+2x

Simplify that to- 2x+2x+2x+8

And also simplify that to- 6x+8

Area- length*width

So, it's (x+4)*2x

which is 2x²+8x

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djyliett [7]
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3 0
3 years ago
Read 2 more answers
Question 1(Multiple Choice Worth 4 points)
Airida [17]
I think you mean x^2 - 7x + 8
This is a basic factoring problem:
What two numbers multiply to make 8 and add to make -7?
There are no two numbers that work!
Therefore, it is prime
4 0
3 years ago
Pls help me I don’t know what to do
aleksandrvk [35]
On what do u Need help on?
3 0
3 years ago
Use the ditributive property for -8 (x / 3)
ioda
Greetings!

"Use the distributive property for -8 (x / 3).<span>"

The distribute property is used to simplify an expression/equation. This is done by multiplying the contents of the parenthesis by the number outside of bracket.

</span>-8 (x / 3)
=(-8*x / -8*3)
<span>Simplify.
</span>=(-8x/-24)


Hope this helps.
-Benjamin



4 0
3 years ago
Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volt
ser-zykov [4K]

Answer:

I(t)=\frac{1}{3}(1-e^{-30t})

Step-by-step explanation:

We are given that

\frac{dI}{dt}+\frac{R}{L}I=\frac{V(t)}{L}

R=150 ohm

L=5 H

V(t)=10 V

P=\frac{R}{L}=\frac{150}{5}=30

I.F=e^{\int Pdt}=e^{\int 30 dt}=e^{30 t}

I(t)\times I.F=\int e^{30 t}\times 10 dt+C

I(t)\times e^{30 t}=\frac{10}{30}e^{30 t}+C

I(t)=\frac{1}{3}+Ce^{-30 t}

I(0)=0

Substitute t=0

0=\frac{1}{3}+C

C=-\frac{1}{3}

Substitute the values

I(t)=\frac{1}{3}-\frac{1}{3}e^{-30 t}

I(t)=\frac{1}{3}(1-e^{-30t})

5 0
3 years ago
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