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Anton [14]
3 years ago
15

A dog travels 18 meters south across the backyard in 11 seconds. What is the dog's speed?

Physics
1 answer:
o-na [289]3 years ago
4 0
The dog’s speed is
A) 0.61 m/s
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How many nanoseconds are there in 1.90 yr ?<br> Express your answer using three significant figures.
shepuryov [24]

       (1.9 yr) x (365.24 day/yr) x (86,400 sec/day) x (10⁹ nsec/sec)

   =  (1.9 x 365.24 x 86,400 x 10⁹) nanosec

   =  6.00 x 10¹⁶ nanoseconds

5 0
3 years ago
A close coiled helical spring of round steel wire 10 mm diameter having 10 complete turns with a mean radius of 60 mm is subject
kow [346]

Answer:

The deflection of the spring is 34.56 mm.

Explanation:

Given that,

Diameter = 10 mm

Number of turns = 10

Radius_{mean} = 60\ mm

Diameter_{mean} = 120\ mm

Load = 200 N

We need to calculate the deflection

Using formula of deflection

\delta=\dfrac{8pD^3n}{Cd^4}

Put the value into the formula

\delta=\dfrac{8\times200\times(120)^3\times10}{80\times10^{3}\times10^4}

\delta =34.56\ mm

Hence, The deflection of the spring is 34.56 mm.

4 0
3 years ago
Our Solar System's planets formed when fragments in space joined together to form growing spheres in a process known as ____​
Nimfa-mama [501]

Answer: accretion......

8 0
4 years ago
Mention two advantage of writing very big and small numbers in tge power of ten.<br>​
Elenna [48]
Easier to write, easier to read, easier to understand, easier to compare
7 0
3 years ago
A stone is thrown with an initial speed of 11.5 m/s at an angle of 50.0 above the horizontal from the top of a 30.0-m-tall build
rewona [7]

Answer:

The magnitude of the horizontal displacement of the rock is 7.39 m/s.

Explanation:

Given that,

Initial speed = 11.5 m/s

Angle = 50.0

Height = 30.0 m

We need to calculate the horizontal displacement of the rock

Using formula of horizontal component

v_{x}=u\cos\theta

Put the value into the formula

v_{x}=11.5\times\cos50

v_{x}=7.39\ m/s

Hence, The magnitude of the horizontal displacement of the rock is 7.39 m/s.

8 0
3 years ago
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