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3 years ago

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2 equal charges, 27 micro Coulomb each, are separated by 5 cm. Find force between those.

1 answer:

padilas [110]3 years ago

3 0

Answer:

The force between charges is $F= 2.624*10^3N$ .

Explanation:

The Coulomb force $F$ between the two charges $q_1$ and $q_2$ separated by distance $d$ is given by the equation

$F = k\dfrac{q_1q_2}{d^2}$

where $k$ is the coulombs constant, and has the value

$k= 9*10^9N\cdot C\cdot m^2$ .

Now in our case

$q_1=q_2=27\mu C =27*10^{-6}C$

and

$d= 5cm =0.05m$ ,

therefore, the Coulomb force between the charges is

$F =( 9*10^9N\cdot C\cdot m^2)*\dfrac{(27*10^{-6}C)(27*10^{-6}C)}{(0.05m)^2}$

$\boxed{ F= 2.624*10^3N}$

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Examples of field force

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Here are some examples of field force:
1. <span>1) electrostatic force of attraction or repulsion on a charged particle in an electric field
2. </span><span>) magnetic force on charged particles moving at right angles with a magnetic field. Magnetic force also affects magnetic poles.

I hope this helps. </span>

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3 years ago

Who was the first person to walk on the moon ?

liq [111]

Answer:

god correct correct

Explanation:

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3 years ago

Read 2 more answers

A spherical balloon has a radius of 7.40 m and is filled with helium. Part A How large a cargo can it lift, assuming that the sk

malfutka [58]

Answer:

The mass of the cargo is $M = 188.43 \ kg$

Explanation:

From the question we are told that

The radius of the spherical balloon is $r = 7.40 \ m$

The mass of the balloon is $m = 990\ kg$

The volume of the spherical balloon is mathematically represented as

$V = \frac{4}{3} * \pi r^3$

substituting values

$V = \frac{4}{3} * 3.142 *(7.40)^3$

$V = 1697.6 \ m^3$

The total mass the balloon can lift is mathematically represented as

$m = V (\rho_h - \rho_a)$

where $\rho_h$ is the density of helium with a value of

$\rho_h = 0.179 \ kg /m^3$

and $\rho_a$ is the density of air with a value of

$\rho_ a = 1.29 \ kg / m^3$

substituting values

$m = 1697.6 ( 1.29 - 0.179)$

$m = 1886.0 \ kg$

Now the mass of the cargo is mathematically evaluated as

$M = 1886.0 - 1697.6$

$M = 188.43 \ kg$

5 0

3 years ago

A point P1 is located by the vector A = (3.74)î + (1.64)ĵ and a point P2 is located by the vector B = (1.60)î + (3.66)ĵ. The vec

seropon [69]

Answer:

$\vec{C} = ( \ - 2.14 \ , \ 2.02 \ )$

Explanation:

The vector that point from point P1 to point P2 its found simply by taking the vector at which point P2 its located and subtracting the vector at which point P1 its located:

$\vec{C} = \vec{B} - \vec{A}$

So:

$\vec{C} = ( \ 1.60 \ , \ 3.66 \ ) - ( \ 3.74 \ , \ 1.64 \ )$

$\vec{C} = ( \ 1.60 \ - \ 3.74 \ , \ 3.66 \ - \ 1.64 \ )$

$\vec{C} = ( \ - 2.14 \ , \ 2.02 \ )$

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3 years ago

A football is place kicked with a velocity having a vertical component of 12 m/s and a horizontal component of 6 m/s. Find the r

SSSSS [86.1K]

The velocity is given by:

V = √(Vx²+Vy²)

V = velocity, Vx = horizontal velocity, Vy = vertical velocity

Given values:

Vx = 6m/s, Vy = 12m/s

Plug in and solve for V:

V = √(6²+12²)

V = 13.42m/s

Now find the direction:

θ = tan⁻¹(Vy/Vx)

θ = angle of velocity off horizontal, Vy = vertical velocity, Vx = horizontal velocity

Given values:

Vx = 6m/s, Vy = 12m/s

Plug in and solve for θ:

θ = tan⁻¹(12/6)

θ = 63.4°

The resultant velocity is 13.42m/s at an angle of 63.4° off the horizontal.

6 0

4 years ago