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almond37 [142]
3 years ago
12

When you go "down" the food chain by continuing to ask "what does it eat?" at what category of living things do you always end u

p?
Physics
1 answer:
Klio2033 [76]3 years ago
7 0

Answer:

Autotrophs

Explanation:

When you go down a food chain continuing to ask "what does it eat?" the last living thing that you will land upon is an autotroph.

Autotrophs are the primary producers as they (photoautotrophs) use the energy either from the sun to prepare  there food by the process of photosynthesis or, more rarely, obtain chemical energy through oxidation (chemoautotrophs) to make organic substances from inorganic ones.

Autotrophs get consumed by the primary consumers in the food chain.

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A 91-kg astronaut and a 1300-kg satellite are at rest relative to the space shuttle. The astronaut pushes on the satellite, givi
WARRIOR [948]

Answer:

18.2145 meters

Explanation:

Using the conservation of momentum, we have that:

m1v1 + m2v2 = m1'v1' + m2'v2'

m1 = m1' is the mass of the astronaut, m2=m2' is the mass of the satellite, v1 and v2 are the inicial speed of the astronaut and the satellite (v1 = v2 = 0), and v1' and v2' are the final speed of the astronaut and the satellite. Then we have that:

0 + 0 = 91*v1' + 1300*0.17

v1' = -1300*0.17/91 = -2.4286\ m/s

The negative sign of this speed just indicates the direction the astronaut goes, which is the opposite direction of the satellite.

If the astronaut takes 7.5 seconds to come into contact with the shuttle, their initial distance is:

distance = 2.4286 * 7.5 = 18.2145\ meters

8 0
4 years ago
A toy train is pushed forward and released at Xi = 4.0 m with a speed of 2.5 m/s. It rolls at a steady speed for 2.0 s, then one
Fittoniya [83]
I don't think that 4m has anything to do with the problem. anyway. here. A___________________B_______C where A is the point that the train was released. B is where the wheel started to stick C is where it stopped From A to B, v=2.5m/s, it takes 2s to go A to B so t=2 AB= v*t = 2.5 * 2 = 5m The train comes to a stop 7.7 m from the point at which it was released so AC=7.7m then BC= AC-AB = 7.7-5 = 2.7m now consider BC v^2=u^2+2as where u is initial speed, in this case is 2.5m/s v is final speed, train stop at C so final speed=0, so v=0 a is acceleration s is displacement, which is BC=2.7m substitute all the number into equation, we have 0^2 = 2.5^2 + 2*a*2.7 0 = 6.25 + 5.4a a = -6.25/5.4 = -1.157 so acceleration is -1.157m/(s^2)
8 0
3 years ago
Read 2 more answers
A car travels for 5.5 h at an average speed<br> of 75 km/h. How far did it travel?<br> T TE
ANEK [815]

Answer:

\boxed {\boxed {\sf 412.5 \ kilometers }}

Explanation:

Distance is the product of speed and time.

d=s*t

The speed of the car is 75 kilometers per hour. It traveled for 5.5 hours.

s= 75 \ km/hr \\t= 5.5 \ hr

Substitute the values into the formula.

d= 75 \ km/hr * 5.5 \ hr

Multiply. Note that the hours will cancel each other out.

d= 75 km * 5.5 \\d= 412.5 \ km

The car travelled <u>412.5 kilometers.</u>

5 0
3 years ago
PLEASE HELPPP!! 40 POINTS! A young man exerted a force of 900 newtons for 10 seconds to push his car. However, he could not get
Dmitrij [34]

No work is done because the object needs to be moved. The formula for work is Work = Force x Distance.

4 0
4 years ago
Which "sphere" does an astronomer most directly study?
Lisa [10]
I would choose B. exosphere. Astronomers study outer space, planets and ect.
5 0
3 years ago
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