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almond37 [142]
3 years ago
12

When you go "down" the food chain by continuing to ask "what does it eat?" at what category of living things do you always end u

p?
Physics
1 answer:
Klio2033 [76]3 years ago
7 0

Answer:

Autotrophs

Explanation:

When you go down a food chain continuing to ask "what does it eat?" the last living thing that you will land upon is an autotroph.

Autotrophs are the primary producers as they (photoautotrophs) use the energy either from the sun to prepare  there food by the process of photosynthesis or, more rarely, obtain chemical energy through oxidation (chemoautotrophs) to make organic substances from inorganic ones.

Autotrophs get consumed by the primary consumers in the food chain.

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Which of the following is a pair of vector quantities?
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Answer:

velocity and displacement answer

Explanation:

thanks me

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3 years ago
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An office heater puts out 2050 btus of energy in the form of heat per hour. given that 1 btus =1.055 kj, how many megajoules of
ivolga24 [154]
<span>Assuming continuous operation (24/7), we can say that

Energy produced : Energy per hour * 24 (number of hours in a day) - 365 (number of days in a year.

Energy per hour: 2050 * 1.055 = 2162.75 kg.

So, we proceed to calculate the results

E: 2162.75 * 24 * 365 = 18,945,690 kj per year.

Now, we transform kj to megajoule, remembering that kilo is 10*3 and mega is 1'*6, so we divide the result by 1,000 in order to get the results in megajoules, and the answer would be:

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3 years ago
(answer fast and correctly and i will give you brainiest and 5 star's. )
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Answer:

Energy cannot be created or destroyed.

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3 years ago
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A 6.2 kg cannonball is fires from a 280 kg cannon. The cannon recoils with a velocity of 4.9 m/s. What is the velocity of the ca
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3 0
3 years ago
a stone is dropped from the top of 50 m high tower simultaneously another stone is thrown upward with a speed of 20 m/s . calcul
Darina [25.2K]
'H' = height at any time
'T' = time after both actions
'G' = acceleration of gravity
'S' = speed at the beginning of time
Let's call 'up' the positive direction.
Let's assume that the tossed stone is tossed from the ground, not from the tower.

For the stone dropped from the 50m tower:

H = +50 - (1/2) G T²

For the stone tossed upward from the ground:

H = +20T - (1/2) G T²

When the stones' paths cross, their <em>H</em>eights are equal.

50 - (1/2) G T² = 20T - (1/2) G T²

Wow !  Look at that !  Add (1/2) G T² to each side of that equation,
and all we have left is:

50 = 20T  Isn't that incredible ? ! ?

Divide each side by 20 :

<u>2.5 = T</u>

The stones meet in the air 2.5 seconds after the drop/toss.

I want to see something: 
What is their height, and what is the tossed stone doing, when they meet ?

Their height is  +50 - (1/2) G T² = 19.375 meters

The speed of the tossed stone is  +20 - (1/2) G T = +7.75 m/s ... still moving up.
I wanted to see whether the tossed stone had reached the peak of the toss,
and was falling when the dropped stone overtook it.  The answer is no ... the
dropped stone was still moving up at 7.75 m/s when it met the dropped one.
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3 years ago
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