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almond37 [142]
3 years ago
12

When you go "down" the food chain by continuing to ask "what does it eat?" at what category of living things do you always end u

p?
Physics
1 answer:
Klio2033 [76]3 years ago
7 0

Answer:

Autotrophs

Explanation:

When you go down a food chain continuing to ask "what does it eat?" the last living thing that you will land upon is an autotroph.

Autotrophs are the primary producers as they (photoautotrophs) use the energy either from the sun to prepare  there food by the process of photosynthesis or, more rarely, obtain chemical energy through oxidation (chemoautotrophs) to make organic substances from inorganic ones.

Autotrophs get consumed by the primary consumers in the food chain.

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Arturiano [62]

Explanation:

A light bulb changes electrical energy into <em>heat energy and light energy .</em>

4 0
3 years ago
Balanced equations account for the conservation of mass.
uranmaximum [27]

Answer:

fff

Explanation:

f

6 0
3 years ago
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A student's calculation for the work done on an object is shown.
MissTica

The statement that describes the error in the work is that the distance must be converted to meters (m).

<h3>FORMULA FOR WORK:</h3>

Work can be calculated by using the following formula:

W = F × d

Where;

  • W = work done
  • F = force (N)
  • d = distance (m)

According to this question, the force is given as 140N and the distance is given as 30cm. The force is calculated as follows:

F = 140N × 30cm = 4200J

This calculation is erroneous because the unit of distance should be converted from cm to meters.

Learn more about work done at: brainly.com/question/3902440

4 0
2 years ago
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Find a model for simple harmonic motion that has an initial displacement (t=0) of 0 inches, an amplitude of 5 inches, and a freq
Svetach [21]

Answer:

The equation of simple harmonic motion is y=5\sin{(8\pi t)}

Explanation:

Given that,

Amplitude = 5 inches

Frequency f= \dfrac{4}{3}

As per the question initial displacement is zero at t = 0 for sine curve.

The displacement is zero so the phase difference will be zero.

We know that,

The general equation of simple harmonic motion

y=A\sin(\omega t+\phi)

Where, A = amplitude

\omega = angular frequency

\phi = phase shift

We need to calculate the time period

Using formula of frequency

f=\dfrac{1}{T}

T=\dfrac{1}{f}

Put the value into the formula

T=\dfrac{1}{\dfrac{4}{3}}

T=\dfrac{3}{4}

We need to calculate the angular frequency

Using formula of angular frequency

\omega=\dfrac{2\pi}{T}

\omega=\dfrac{2\pi\times4}{3}

Put the value into the general equation

y=5\sin{(8\pi t)}

Hence, The equation of simple harmonic motion is y=5\sin{(8\pi t)}

7 0
3 years ago
A boy kicks a football from ground level. The ball takes 3 seconds to reach its maximum height. What is the angle of the initial
ruslelena [56]
<h2>The angle of the initial velocity with respect to the horizontal is 85.14°</h2>

Explanation:

Given that the ball takes 3 seconds to reach its maximum height.

Consider the vertical motion of ball till maximum height.

We have equation of motion v = u + at

     Acceleration, a = -9.81 m/s²

     Final velocity, v = 0 m/s    

     Time, t = 3 s

     Substituting

                      v = u + at  

                      0 = u + -9.81 x 3

                      u = 29.43 m/s

Initial vertical velocity is 29.43 m/s.

Now consider horizontal motion of ball.

Time of flight of ball = 2 x Time to reach maximum height = 2 x 3 = 6 s

Displacement = 15 m

We have equation of motion s = ut + 0.5 at²

        Displacement, s = 15 m

        Acceleration, a = 0 m/s²  

        Time, t = 6 s      

     Substituting

                      s = ut + 0.5 at²

                      15 = u x 6 + 0.5 x 0 x 6²

                      u = 2.5 m/s

Initial horizontal velocity is 2.5 m/s

Let r be the initial velocity and θ be the angle with horizontal

              Initial vertical velocity = rsinθ = 29.43 m/s

              Initial horizontal velocity = rcosθ = 2.5 m/s

Dividing

              \frac{rsin\theta }{rcos\theta }=\frac{29.43}{2.5}\\\\tan\theta=11.77\\\\\theta=85.14^0

The angle of the initial velocity with respect to the horizontal is 85.14°

4 0
3 years ago
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