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MrRissso [65]
3 years ago
12

Which free body diagram is in equilibrium? Question 5 options:

Physics
1 answer:
melamori03 [73]3 years ago
5 0

A I think sorry if its wrong

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Jane is sliding down a slide. What kind of motion is she demonstrating?
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When Jane is sliding down a slide, she is demonstrating translational motion. 
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How much tension must a cable withstand if it is used to accelerate a 1800-kg car vertically upward at 0.80 m/s2 ?
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Force =tension =mass x acceleration 

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3. At an early age, what happened to Cesar’s home?
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3 years ago
A 3.1 kg ball is thrown straight upward with a speed of 18.2 m/s. Use conservation of energy to calculate the maximum height the
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Answer:

h = 16.9 m

Explanation:

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h = (0.5)(Vf² - Vi²)/g

where,

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Vi = Initial Speed of Ball = 18.2 m/s

g = acceleration due to gravity = - 9.8 m/s² ( negative for upward motion)

h = maximum height the ball can reach = ?

Therefore, using values in the equation, we get:

h = (0.5)[(0 m/s)² - (18.2 m/s)²]/(-9.8 m/s²)

<u>h = 16.9 m</u>

4 0
3 years ago
A 20.0-kg rock is sliding on a rough, horizontal surface at 8.00 m/s and eventually stops due to friction. The coefficient of ki
Neporo4naja [7]

Answer:

a = -1.961\,\frac{m}{s^{2}}, s = 16.318\,m, t = 4.079\,s

Explanation:

The equations of equilibrium for the rock are:

\Sigma F_{x} = -\mu_{k}\cdot N = m \cdot a

\Sigma F_{y} = N - m\cdot g = 0

After some algebraic handling, the following expression is found:

-\mu_{k}\cdot m \cdot g = m \cdot a

-\mu_{k}\cdot g = a

Deceleration experimented by the rock is:

a = - (0.2)\cdot (9.807\,\frac{m}{s^{2}} )

a = -1.961\,\frac{m}{s^{2}}

The distance travelled by the rock before stopping is:

s = \frac{(0\,\frac{m}{s} )^{2}-(8\,\frac{m}{s} )^{2}}{2\cdot (-1.961\,\frac{m}{s^{2}} )}

s = 16.318\,m

And the time is:

t = \frac{0\,\frac{m}{s}-8\,\frac{m}{s}}{(-1.961\,\frac{m}{s^{2}} )}

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