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MrRissso [65]
3 years ago
12

Which free body diagram is in equilibrium? Question 5 options:

Physics
1 answer:
melamori03 [73]3 years ago
5 0

A I think sorry if its wrong

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List an example of each of the four classes polymers that living things make and use
slamgirl [31]


The four classes of polymers are:

1. Nucleic acids.  Examples are DNA and RNA

2. Protein. Examples are enzymes and hemoglobin

3. Carbohydrates. Examples as starch and glycogen

4. Lipids. Examples are triglycerides and phospholipids

The building blocks of nucleic acids are called bases and there are four types known as Guanine, Adenine, Thymine and Cytosine.

The building blocks of carbohydrates are glucose molecules.

The building blocks of protein are amino acids.

The building blocks of lipids are a combination of fatty acids and glycerol.

6 0
3 years ago
5. How will you separate water from petrol?
ohaa [14]

Answer:

by a seprating funnel or let it stand it will settle on its own

Explanation:

5 0
3 years ago
Read 2 more answers
How do prokaryotic cells replicate?
Alika [10]

Answer:

The usual method of prokaryote cell division is termed binary fission. The prokaryotic chromosome is a single DNA molecule that first replicates, then attaches each copy to a different part of the cell membrane. When the cell begins to pull apart, the replicate and original chromosomes are separated.

6 0
3 years ago
What determines how much induced current will flow through a conductor?
Vitek1552 [10]

Answer:

Rate of change of magnetic flux

Explanation:

The induced current is equal to the ratio of induced emf to the resistance of the conductor.

According to the Faraday's law of electromagnetic induction, the induced emf is proportional to the rate of change of magnetic flux.

7 0
2 years ago
nert xenon actually forms many compounds, especially with highly electronegative fluorine. The ΔH o f values for xenon difluorid
loris [4]

Answer:

For Xenon fluoride, the average bond energy is 132kj/mol

For tetraflouride,the average bond energy is 150.5kj/mol.

For hexaflouride, the average bond energy is 146.5 kj/mol

Explanation:

For xenon fluoride

105/2 = 52.5

For F-F

159/2 = 79.5

Average bond energy of Xe-F = 79.5 + 52.5 = 132kj/mole

For tetraflouride

284/4 = 71

For F-F

159/2 = 79.5

Average bond energy = 79.5 + 71 = 150.5kj/mol

For hexaflouride

402/6 = 67

F-F = 159/2 = 79.5

Average bond energy = 67 + 79.5 = 146.5kj/ mol

3 0
3 years ago
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