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2 years ago

What is the value of x, given that figure PTRA is an iscosceles trapezoid

Mathematics

2 answers:

kondor19780726 [428]2 years ago

8 0

<span>D. 98 hfueiowpahguifra[gf</span>

Westkost [7]2 years ago

3 0

Well it think the answer is D.98

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In converting 9 yards to inches, what unit (omit the number) would you place in the numerator of your ratio? Use the plural form

Yanka [14]

Let
X/Y--------> the ratio

we know that

X/Y units --------> are inches/yards
9 yards*(X/Y ) inches/yards-------> 9*X/Y yards*inches/yards----> 9*X/Y inches
the ratio in this problem is (X/Y inches /yards)-------> 36/1 inches/yards
the unit in the numerator of the ratio is inches

the answer is
inches

6 0

2 years ago

An orange traffic cone has a diameter of 10 in. and a height of 28 in.

masha68 [24]

Answer:

733 inches

Step-by-step explanation:

V= 3.14*5^2*28/3

Order of Operations (PEMDAS)

5^2=25

25*3.14= 78.5

78.5*28= 2198

2198/3=732.66

Round to nearest cubic inch

733 inches

8 0

2 years ago

If f(x)=2x-6 and g(x)=3x+9, find (f+g)(x)

anyanavicka [17]

Answer:

<em>(f+g)(x) </em>= 5x + 3

Step-by-step explanation:

7 0

2 years ago

Standard form of 5.65 x 10-3?

Ad libitum [116K]

Answer:

53.5

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m

rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}$

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}$

$\text{Fuel used by 1st auto}=30 \text{ gallons}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}$

$\text{Fuel used by 2nd auto}=20 \text{ gallons}$

Let us find the difference of fuel used by both autos.

$\text{Number of gallons that 2nd auto used less than 1st auto}=30-20$

$\text{Number of gallons that 2nd auto used less than 1st auto}=10$

Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces $5\times 10=50$ pounds of carbon.

Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

8 0

2 years ago