Whats the answer to 45 + 54 ÷ p

The blood pressure at your heart is approximately 100 mm Hg. As blood is pumped from the left ventricle of your heart, it flows

RoseWind [281]

Answer:

The correct option is c. 75 for this question

Explanation:

The correct option is c. 75 for this question:

Let's see how.

Continuity Equation is given as:

AcVc = AaVa

Where,

Aa = Area of Aorta

Ac = Area of the capillary

Va = Fluid speed in Aorta

Vc = Fluid speed in Capillary

So,

Assuming the fluid is the ideal one/

$\pi$ /4 $Dc^{2}$ Vc= $\pi$ /4 $Da^{2}$ Va

$Dc^{2}$ Vc= $Da^{2}$ Va

Dc = Da x $\sqrt{\frac{Va}{Vc} }$

Dc = 2.5 cm x $\sqrt{\frac{60 cm}{0.07 cm } }$

Dc = 73.192 cm

Dc = 75 approximately

Hence, the diameter of the capillary = 75 cm approximately

3 0

3 years ago

A 1500-kg car traveling east with a speed of 25.0 m/s collides at an intersection with a 2500-kg van traveling north at a speed

IgorC [24]

Answer:

The direction and magnitude of velocity is 38.65° and 12.005 m/s

Explanation:

Given that,

Mass of car = 1500 kg

Speed of car = 25.0 m/s

Mass of van = 2500 kg

Speed of van =20.0 m/s

We need to calculate the velocity

Using conservation of energy

$m_{c}u_{i}+m_{v}u_{i}=(m_{c}+m_{v})v_{f}$

$1500(25i+0j)+2500(0+20j)=4000(v_{f})$

$v_{f}=\dfrac{1500\times25}{4000}i+\dfrac{1500\times20}{4000}j$

$v_{f}=9.375 i+7.5 j$

The magnitude of velocity

$|v_{f}|=\sqrt{(9.375)^2+(7.5)^2}$

$|v_{f}|=12.005\ m/s$

We need to calculate the direction

$\tan\theta=\dfrac{coefficient\ of\ j}{coefficient\ of\ i}$

$\tan\theta=\dfrac{7.5}{9.375}$

$\theta=\tan^{-1}0.8$

$\theta=38.65^{\circ}$

Hence, The direction and magnitude of velocity is 38.65° and 12.005 m/s.

3 0

4 years ago

The average lifetime of a poodle dog is 13.0 years. How fast is it traveling, u, relative to an observer who measures the averag

bogdanovich [222]

Answer:

The speed is 0.97 c.

Explanation:

Given that,

Dilated time t'= 50.0 years

Rest time t = 13.0 years

We need to calculate the speed

Using formula of time dilation

$t'=\dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}}}$

Where, t' = change in time

t = rest time

v = velocity

c = speed of light

Put the value into the formula

$50.0=\dfrac{13.0}{\sqrt{1-\dfrac{v^2}{(3\times10^{8})^2}}}$

$v^2=\dfrac{(13)^2\times(c)^2-(c)^2\times50^2}{50^2}$

$v^2= 0.9324c^2$

$v=0.97c$

Hence, The speed is 0.97 c.

6 0

3 years ago

A marble is flicked off the edge of a table. The motion of the marble follows a parabolic path.

dem82 [27]

When marble is flicked off the edge of a table then the at the instant it will move off the table the velocity is horizontal while due to force of gravitation the marble will start accelerating downwards.

So here we will say that the velocity of marble will remain constant through out the motion in X direction as there is no force in that direction

While in Y direction the marble will have gravitational force due to which marble will accelerate downwards

So the path of the marble will be parabolic path

hence the correct answer will be

<em>Only one continuous force is acting on the marble.</em>

5 0

4 years ago

8.

svetoff [14.1K]

Answer:

9.5 seconds

Explanation:

You need to make the ending speed into meters per sec.

So it would be 120km/h = 33.33m/s

If the acceleration rate is 3.5m/s, then the final answer would equal to 9.5 seconds

Also btw rounding it up is a good idea too so 10 seconds if you round

8 0

3 years ago

Whats the answer to 45 + 54 ÷ p - q