Whats the answer to 45 + 54 ÷ p

A 16.2 kg person climbs up a uniform ladder with negligible mass. The upper end of the ladder rests on a frictionless wall. The

S_A_V [24]

To solve this problem we will apply the concepts related to the balance of forces. We will decompose the forces in the vertical and horizontal sense, and at the same time, we will perform summation of torques to eliminate some variables and obtain a system of equations that allow us to obtain the angle.

The forces in the vertical direction would be,

$\sum F_x = 0$

$f-N_w = 0$

$N_w = f$

The forces in the horizontal direction would be,

$\sum F_y = 0$

$N_f -W =0$

$N_f = W$

The sum of Torques at equilibrium,

$\sum \tau = 0$

$Wdcos\theta - N_wLsin\theta = 0$

$WdCos\theta = fLSin\theta$

$f = \frac{Wd}{Ltan\theta}$

The maximum friction force would be equivalent to the coefficient of friction by the person, but at the same time to the expression previously found, therefore

$f_{max} = \mu W=\frac{Wd}{Ltan\theta}$

$\theta = tan^{-1} (\frac{d}{\mu L})$

Replacing,

$\theta = tan^{-1} (\frac{0.9}{0.42*2})$

$\theta = 46.975\°$

Therefore the minimum angle that the person can reach is 46.9°

8 0

2 years ago

Calculate the pressure exerted on the heel of a boy’s foot if the boy weighs 80 N and he lands on one heel,which has an area of

cricket20 [7]

Pressure at a given surface is given as ratio of normal force and area

so here force due to heel of the shoes is given as 80 N

and the area of the heel is given as 16 cm^2

so we can say

$P = \frac{F}{A}$

here we have

F = 80 N

$A = 16 cm^2 = 16 * 10^{-4} m^2$

$P = \frac{80}{16 * 10^{-4}}$

$P = 5 * 10^4 N/m^2$

so pressure at the surface due to its heel will be 5 * 10^4 N/m^2

3 0

3 years ago

How does free energy challenge the scientific definition of energy?

gtnhenbr [62]

Free Energy is a thermodynamic quantity given by the subtraction between the internal energy of a system and the product of its absolute temperature and entropy.
 In physics, the ability to do work.

I may not be completely sure but compare those 2 things together and you should find your answer.

7 0

2 years ago

A charge of +0.001 C is 1 m to your right and another charge of +1000 C is 1 m to your left. You are holding a charge of −1 C. W

almond37 [142]

Answer:

C and D

Explanation:

Charge on right = +0.001 C

Charge on left = 1000 C

Charge held in between = -1C

Ratio between right and left charge:

$=\frac{1000}{.001}\\\\=1\times 10^6$

Which shows charge on left exerts 1,000,000 times more force then charge on right

Charge on left is 1000 times greater in magnitude than charge held between and charge held between is 1000 times greater in magnitude than charge on right. So the magnitude of the force on the charge you are holding would be the same if it were +1 C instead of −1 C.

8 0

2 years ago

An athlete is running at a constant velocity with a javelin held in his right hand. The force he is applying on the javelin as h

Paladinen [302]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Since the force he is applying is 5N and he carries it a distance of 10 meters and the displacement and the force are assumed to be in the same direction we have 5*10 so 50 J

5 0

2 years ago

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Whats the answer to 45 + 54 ÷ p - q