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4 years ago

Which equation represents mass-energy equivalence? E = m2c E = mc2 E = (mc)2 E = mc

Physics

2 answers:

motikmotik4 years ago

4 0

Einstein's energy mass equivalence relation say that if the whole given mass is converted to energy then it would be

$E = mc^2$

where

m = mass in kg

c = speed of light in m/s

this is the origination of quantum physics and by this formula we can relate the dual nature of light and particle

So correct relation above will be

$E = mc^2$

const2013 [10]4 years ago

4 0

the answer is B i just took it

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A thin 1.5 mm coating of glycerine has been placed between two microscope slides of width 0.8 cm and length 3.9 cm . Find the fo

Radda [10]

The force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is zero.

<h3>Force required to pull one end at a constant speed</h3>

The force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is determined by applying Newton's second law of motion as shown below;

F = ma

where;

m is mass
a is acceleration

At a constant speed, the acceleration of the object will be zero.

F = m x 0

F = 0

Thus, the force required to pull one of the microscope sliding at a constant speed of 0.28 m/s relative to the other is zero.

Learn more about constant speed here: brainly.com/question/2681210

3 0

2 years ago

A skater goes into a spin with her arms pulled in (close to her body). When she stretches her arms out: A) her angular speed ω d

musickatia [10]

Answer:

When she stretches her arms out, B) her angular speed ω increases due to her moment of inertia decreasing

Explanation:

The angular momentum of a rotating object is defined as the product of its moment of inertia and angular speed.

L = I ω

where

L is the angular momentum
I is the moment of inertia
ω is the angular speed

According to the principle of conservation of angular momentum, if there is no external torque, angular momentum of the skater must remain conserved. If the initial and final moment of inertia is I_i and I_f while corresponding angular velocities are ω_i and ω_f , then the principle of conservation of angular momentum can be expressed as the following equation:

(I_f) (ω_f) = (I_i) (ω_i)

ω_f / ω_i = I_i / I_f

From the expression above, we can see that if the moment of inertia decreases, angular velocity would increase to conserve angular momentum of the skater.

Therefore, When she stretches her arms out, her angular speed ω increases due to her moment of inertia decreasing.

5 0

4 years ago

Need answer ASAP!!!

Alina [70]

Hello!

Use ohm law:

I = V / R

Replacing:

I = 100 V / 20 O

I = 5 A

The current is 5 amperes.

5 0

3 years ago

The courtroom role that possesses the most discretion is?

KonstantinChe [14]

The role of the Prosecutor's

5 0

3 years ago

A 0.500-kg mass suspended from a spring oscillates with a period of 1.18 s. How much mass must be added to the object to change

olga55 [171]

Answer:

The add mass = 5.465 kg

Explanation:

Note: Since the spring is the same, the length and Tension are constant.

f ∝ √(1/m)........................ Equation 1 (length and Tension are constant.)

Where f = frequency, m = mass of the spring.

But f = 1/T ..................... Equation 2

Substituting Equation 2 into equation 1.

1/T ∝ √(1/m)

Therefore,

T ∝ √(m)

Therefore,

T₁/√m₁ = k

where k = Constant of proportionality.

T₁/√m₁ = T₂/√m₂ ........................ Equation 3

making m₂ the subject of the equation

m₂ = T₂²(m₁)/T₁²........................... Equation 4

Where T₁ = initial, m₁ = initial mass, T₂ = final period, m₂ = final mass.

Given: T₁ = 1.18 s m₁ = 0.50 kg, T₂ = 2.07 s.

Substituting into equation 4

m₂ = (2.07)²(0.5)/(1.18)²

m₂ = 4.285(1.392)

m₂ = 5.965 kg.

Added mass = m₂ - m₁

Added mass = 5.965 - 0.5

Added mass = 5.465 kg.

Thus the add mass = 5.465 kg

7 0

3 years ago