Answer:
I think its 2. It would decrease
Explanation:
Hope this helps
Impulse is the integral of a force, F.
Hope this helps.
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Answer:
1. 3 m
2. 27 s
Explanation:
1. "A car traveling at +33 m/s sees a red light and has to stop. If the driver can accelerate at -5.5 m/s², how far does it travel?"
Given:
v₀ = 33 m/s
v = 0 m/s
a = -5.5 m/s²
Unknown: Δx
To determine the equation you need, look for which variable you don't have and aren't solving for. In this case, we aren't given time and aren't solving for time. So look for an equation that doesn't have t in it.
Equation: v² = v₀² + 2aΔx
Substitute and solve:
(0 m/s)² = (33 m/s)² + 2(-5.5 m/s²) Δx
Δx = 3 m
2. "A plane starting from rest at one end of a runway accelerates at 4.8 m/s² for 1800 m. How long did it take to accelerate?"
Given:
v₀ = 0 m/s
a = 4.8 m/s²
Δx = 1800 m
Unknown: t
Equation: Δx = v₀ t + ½ a t²
Substitute and solve:
1800 m = (0 m/s) t + ½ (4.8 m/s²) t²
t ≈ 27 s
-- <u><em>Current is measured in amps.</em></u> (You can use any symbol you want to represent current, but the most common one is " I ", not "Δ".)
-- <u><em>The relationship between current, voltage, and resistance is mathematically defined by Ohm's Law. </em></u>
-- <u><em>Current is the flow of electrons through a circuit.</em></u>
-- (Ohm's Law is NOT mathematically represented by the equation V=I/R.) <u><em>It should be V = I · R</em></u> .
(When solving for Resistance in a circuit and both voltage and current are known values, the equation I =V*R is not true, and not the way to solve it.) <u><em>If the resistance is what you're looking for, then the equation to use is </em></u><u><em>R = V / I</em></u><u><em> . </em></u>
<em>-- </em><u><em>If the voltage in a circuit is increased, the current will also increase.</em></u>
Answer:
1) Can change the state of an object(rest to motion/ motion to rest):For example, pushing a heavy stone in order to move it. 2) May change the speed of an object if it is already moving. 4) May bring about a change in the shape of an object. For example, blowing air in balloon.