Answer:
![f=4.70\times 10^{14}\ Hz](https://tex.z-dn.net/?f=f%3D4.70%5Ctimes%2010%5E%7B14%7D%5C%20Hz)
Explanation:
Given that,
The wavelength of light, ![\lambda=6.38\times 10^{-7}\ m](https://tex.z-dn.net/?f=%5Clambda%3D6.38%5Ctimes%2010%5E%7B-7%7D%5C%20m)
We need to find the frequency of the light. We know that,
![c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{6.38\times 10^{-7}}\\\\f=4.70\times 10^{14}\ Hz](https://tex.z-dn.net/?f=c%3Df%5Clambda%5C%5C%5C%5Cf%3D%5Cdfrac%7Bc%7D%7B%5Clambda%7D%5C%5C%5C%5Cf%3D%5Cdfrac%7B3%5Ctimes%2010%5E8%7D%7B6.38%5Ctimes%2010%5E%7B-7%7D%7D%5C%5C%5C%5Cf%3D4.70%5Ctimes%2010%5E%7B14%7D%5C%20Hz)
So, the required frequency of light is equal to
.
Answer:
v = 17.71 m / s
Explanation:
We can work this exercise with the kinematics equations. In general the body is released so that its initial velocity is zero, the acceleration of the acceleration of gravity
v² = v₀² - 2 g (y -y₀)
v² = 0 - 2g (y -y₀)
when it hits the stone the height is zero and part of the height of the seagull I
v² = 2g y₀
v = Ra (2g i)
let's calculate
v =√ (2 9.8 16)
v = 17.71 m / s
Answer:
d) KEe = KEp
Explanation:
According to the law of conservation of energy, the electric potential energy is converted into the kinetic energy of the particle:
![KE=U\\KE=qV](https://tex.z-dn.net/?f=KE%3DU%5C%5CKE%3DqV)
Here, q is the particle's charge and V is the potential difference.
The charge of the electron is -e. So:
![KE_e=-eV\\KE_e=-e(1V)](https://tex.z-dn.net/?f=KE_e%3D-eV%5C%5CKE_e%3D-e%281V%29)
The charge of the proton is e. So:
![KE_p=eV\\KE_p=e(-1V)\\KE_p=-e(1V)](https://tex.z-dn.net/?f=KE_p%3DeV%5C%5CKE_p%3De%28-1V%29%5C%5CKE_p%3D-e%281V%29)
So ![KE_e=KE_p](https://tex.z-dn.net/?f=KE_e%3DKE_p)
Answer:
The answer is C because there is no friction there will be no friction force only applied and since its on ice you have to account for gravity
Explanation: