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sammy [17]
2 years ago
9

Which accounts for an increase in the temperature of a gas that is kept a constant volume

Physics
1 answer:
oksian1 [2.3K]2 years ago
7 0

Answer:

An increase in pressure

Explanation:

The ideal gas law states that:

pV=nRT

where

p is the gas pressure

V is the volume

n is the number of moles

R is the gas constant

T is the temperature of the gas

in the equation, n and R are constant. For a gas kept at constant volume, V is constant as well. Therefore, from the formula we see that if the temperature (T) is increase, the pressure (p) must increase as well.

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When three people with a total mass of 2.00 x 102 kg step into their 1.200 x 103 kg car, the car’s
Aleksandr-060686 [28]

Answer:

a

 k =  457333.3 N/m

b

x_a  =0.09\ m      

Explanation:

From the question we are told that

    The total mass of  three people is  M  = 2.00*10^{2} \ kg

     The mass of the car is  m_c  =  1.200 *10^{3} \ kg

     The compression of the car spring is  x = 3 \ cm  = 0.03 \ m

     

Generally the spring constant is mathematically represented as

          k =  \frac{F}{x}

Here F is the force exerted by the mass of three people and that of the car , this is mathematically represented as        

=>       F = (M +m_c) *g

=>       F = ([2.0*10^{2} ]+[ 1.200*10^{3}]) * 9.8

=>       F = 13720 \  N

So

        k =  \frac{13720}{0.03}

=>     k =  457333.3 N/m

Generally if the mass which the car is loaded with is  m  =  3.00*10^{2} \ kg

Then the force experienced by the spring is  

         =>       F_a = (m +m_c) *g

         =>       F_a = (3.00*10^{3} + 1.200 *10^{3}) * 9.8

         =>       F_a = 41160 \  N

Generally from the above formula the compression is  

       x_a  = \frac{F_a}{k}

=>    x_a  = \frac{41160}{457333.3}

=>    x_a  =0.09\ m      

3 0
3 years ago
I need to find 1).a,b,c
Aleksandr [31]
Let's cut through the weeds and the trash
and get down to the real situation:

                  A stone is tossed straight up at  5.89 m/s .
                  Ignore air resistance.


Gravity slows down the speed of any rising object by  9.8 m/s every second.
So the stone (aka Billy-Bob-Joe) continues to rise for

                     (5.89 m/s / 9.8 m/s²)  =  0.6 seconds.

At that timer, he has run out of upward gas.  He is at the top
of his rise, he stops rising, and begins to fall.

His average speed on the way up is  (1/2) (5.89 + 0) = 2.945 m/s .

Moving for 0.6 seconds at an average speed of  2.945 m/s,
he topped out at

                    (2.945 m/s) (0.6 s) =  1.767 meters above the trampoline.

With no other forces other than gravity acting on him, it takes him
the same time to come down from the peak as it took to rise to it.

   (0.6 sec up) + (0.6 sec down)  =  1.2 seconds until he hits rubber again.



 
5 0
3 years ago
Two people are each
docker41 [41]

Answer:

the rope should break

Explanation:

she with equal amounts of pulling are on each side then the rope should slowly start to tare apart and snap/break.

hope this helps you

3 0
2 years ago
What is the acceleration of a proton moving with a speed of 6.5 m/s at right angles to a magnetic field of 1.5 T?
Brilliant_brown [7]

Answer:

The acceleration of the proton is 9.353 x 10⁸ m/s²

Explanation:

Given;

speed of the proton, u =  6.5 m/s

magnetic field strength, B = 1.5 T

The force of the proton is given by;

F = ma = qvB(sin90°)

ma = qvB

where;

m is mass of the proton, = 1.67 x 10⁻²⁷ kg

charge of the proton, q = 1.602 x 10⁻¹⁹ C

The acceleration of the proton is given by;

a = \frac{qvB}{m}\\\\a = \frac{(1.602*10^{-19})(6.5)(1.5)}{1.67*10^{-27}}\\\\a = 9.353*10^8 \ m/s^2

Therefore, the acceleration of the proton is 9.353 x 10⁸ m/s²

4 0
2 years ago
When you step inside a warm ski lodge on a cold day, you find your glasses fog. why does this occur?
marin [14]
Answer: Condensation of moisture in the air onto the glasses.

Explanation:
When you come from a cold environment into a warm ski lodge, the glasses are at a much lower temperature than that of the lodge.
Because the air in the room contains moisture (water vapor), it condenses on a surface whose temperature is lower than the dew point of the room. 
5 0
3 years ago
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