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Mumz [18]
3 years ago
7

Tony has a mass of 50 kg, and his friend Sam has a mass of 45 kg. Assume that both friends push off on their roller blades with

the same force. Explain which boy will have greater acceleration.
Tony will have greater acceleration for a given amount of force.
Sam will have greater acceleration due to greater mass.
Tony will have greater acceleration due to greater velocity.
Sam will have greater acceleration for a given amount of force.
Physics
1 answer:
wolverine [178]3 years ago
3 0
I believe it is D because if the mass is smaller then greater the acceleration for it to be equal force. Hope this helps! Sorry, if I'm wrong. 
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What are Sir Issac Newton's three laws of motion?
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The second law is that the acceleration of an object is dependent upon two variables. the net force acting upon the object and the mass of the object.  F= ma or force is equal to mass times acceleration. This law is known as the law of force and acceleration.  

The third law is that for every action there is an equal and opposite reaction.  every interaction there is a pair of forces acting on the two interacting objects. the size of forces on the first object equals the size of the force on the second object. 

Hope this helps :) 

can you please make this the brainliest answer it would really help . Thanks
4 0
3 years ago
Read 2 more answers
PLEASE HELP:
mojhsa [17]
The marble's volume is equal to 1.2 cm^{3}
Density= mass/volume
Mass= 3.05 Grams
Volume= 1.2 cm^3
3.05/1.2= 2.92 <span>g/mL</span>

7 0
3 years ago
For convection to occur,
asambeis [7]

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4 0
3 years ago
Not in book
umka2103 [35]

Answer:

x=2.4365\ m

and

x=-1.4365\ m

Explanation:

Given:

  • first charge, q_1=5\times 10^{-3}\ C
  • second charge, q_2=3\times 10^{-3}\ C
  • position of first charge, x_1=-2\ m
  • position of second charge, x_2=-1\ m

Now since there are only 2 charges and of the same sign so they repel each other. This repulsion will be zero at some point on the line joining the charges.

<u>Now, according to the condition, electric field will be zero where the effects of field due to both the charges is equal.</u>

E_1=E_2

  • since first charge is greater than the second charge so we may get a point to the right of the second charge and the distance between the two charges is 1 meter.

\frac{1}{4\pi.\epsilon_0} \frac{q_1}{(r+1)^2} =\frac{1}{4\pi.\epsilon_0} \frac{q_2}{(r)^2}

\frac{5\times 10^{-3}}{(r+1)^2} = \frac{3\times 10^{-3}}{(r)^2}

3(r^2+1+2r)=5r^2

2r^2-6r-3=0

r=3.4365 \&\ r=-0.4365

Since we have assumed that the we may get a point to the right of second charge so we calculate with respect to the origin.

x=-1+3.4365=2.4365\ m

and

x=-1-0.4365=-1.4365\ m

6 0
3 years ago
How do objects with the same charge interact? How do objects with opposite charges interact?
Marta_Voda [28]
Objects with the same charge repels each other whereas objects with opposite charges attract each other.

Hope this helps!
3 0
3 years ago
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