Answer:
Formular of kinteic energy is 0.5 × (mass x velocity)²
0.5 × 2500 kg × 35² =1,531,250 jules
Answer:
Explanation:
The law of inertia states that if an object is in motion will remain in motion unless an external force is applied to it.
law of inertia for the rotating system in terms of angular momentum states that the angular momentum of a system will remain the same unless an external torque is applied to the system.
External Torque either increases or decreases the angular velocity thus changing angular momentum.
the above three pictures may help you
go through the attachments
Answer:
The specific heat addition is 773.1 kJ/kg
Explanation:
from table A.5 we get the properties of air:
k=specific heat ratio=1.4
cp=specific heat at constant pressure=1.004 kJ/kg*K
We calculate the pressure range of the Brayton cycle, as follows
n=1-(1/(P2/P1)^(k-1)/k))
where n=thermal efficiency=0.5. Clearing P2/P1 and replacing values:
P2/P1=(1/0.5)^(1.4/0.4)=11.31
the temperature of the air at state 2 is equal to:
P2/P1=(T2/T1)^(k/k-1)
where T1 is the temperature of the air enters the compressor. Clearing T2
11.31=(T2/290)^(1.4/(1.4-1))
T2=580K
The temperature of the air at state 3 is equal to:
P2/P1=(T3/T4)^(k/(k-1))
11.31=(T3/675)^(1.4/(1.4-1))
T3=1350K
The specific heat addition is equal to:
q=Cp*(T3-T2)=1.004*(1350-580)=773.1 kJ/kg
We have to employ Newton's Second Law and Third Law here: force = mass * acceleration, and every force produces an equal and opposite force.
—The forces vertically are EQUAL, so no acceleration is occurring in this direction. This also means that the force of gravity and the normal force must be equal in magnitude.
—The forces horizontally are NOT equal, so there will be acceleration on this box in this direction. The applied force is going to be larger than the friction force, and the friction force opposes the direction of the applied force.
First, we find the weight of this box, which is given by mass * acceleration due to gravity. On Earth, acceleration due to gravity is about 9.8 m/s^2.
So, 70 kg * 9.8 m/s^2 = 686 N. This force points downwards.
The normal force is equal in magnitude to this, so it is also = 686 N, but points upwards.
The force of friction is given by force(friction) = µ * force(normal). In this problem, µ = 0.50. Then, we plug in to get 0.50 * 686 N = 343 N. This is the force of friction that opposes the motion of the box.
And finally, we are given the applied force, which is 400 N.
Now we make a Newton's second law equation.
force(applied) - force(friction) = mass * acceleration
400 N - 343 N = 70 kg * a
a = .8142 m/s^2
I really hope this is the right answer; it's 4 AM for me lol
