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Anni [7]
3 years ago
7

Difference between regular and irregular object.​

Physics
1 answer:
DaniilM [7]3 years ago
5 0
<h2><em>Answer:</em></h2><h2><em>Regular </em><em>object</em></h2>
  • <em>Those </em><em>substance </em><em>which </em><em>have </em><em>fixed </em><em>geometrical </em><em>shape </em><em>are </em><em>called </em><em>regular </em><em>object.</em>
  • <em>For </em><em>example</em><em>:</em><em> </em><em>books,</em><em>pencils,</em><em> </em><em>basketball</em><em> </em><em>etc.</em>
<h2><em>Irregular </em><em>object</em></h2>
  • <em>Those </em><em>substance </em><em>which </em><em>do </em><em>not </em><em>have </em><em>geometrical</em><em> </em><em>shape </em><em>are </em><em>called </em><em>irregular</em><em> </em><em>object</em><em>.</em>
  • <em>For </em><em>example:</em><em> </em><em>a </em><em>piece </em><em>of </em><em>stone,</em><em>a </em><em>broken </em><em>piece </em><em>of </em><em>brick,</em><em>leaf </em><em>etc.</em>

<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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A student pushes a 2.85 kg cart causing it to accelerate at a rate of 4.9 m/s squared .What amount of force must the student hav
uysha [10]
In order to find the force (F), you would have to use the formula for it:
F=ma
where m is mass and a is acceleration.
In the problem, the mass is 2.85kg and the acceleration is 4.9m/s^2.
Therefore,
F=2.85kg(4.9m/s^2)
F=13.965kg(m/s^2)
Since N=kg(m/s^2)
F=13.965N
And because the problem requires that we use only 2 significant figures,
F=13N
Therefore, the student must exert 13N of force.

7 0
3 years ago
Two small insulating spheres with radius 3.50×10−2 m are separated by a large center-to-center distance of 0.555 m. One sphere i
xz_007 [3.2K]

Answer:

E = 7.83 \times 10^5 N/C

Explanation:

Since we know that two sphere is oppositely charged so net electric field at the mid point of two balls will be sum of the electric field due to each ball at the mid point

So we know that

E = \frac{kq_1}{r^2} + \frac{kq_2}{r^2}

here we know that

q_1 = 4.20 \mu C

q_2 = 2.50 \mu C

r = \frac{0.555}{2}

so we have

E = \frac{(9\times 10^9)(4.20 + 2.50) \times 10^{-6}}{0.2775^2}

E = 7.83 \times 10^5 N/C

4 0
3 years ago
A bus start from rest. If the acceleration of bus is 0.5 m/s square. what will be its velocity at the end of 2 minutes?what will
Andrej [43]

Answer:

3586

Explanation:

by using formula s=it+0.5at^2

5 0
2 years ago
Read 2 more answers
Since Mars is smaller, how can it have an equal landmass?
Kruka [31]
With smaller mass, object should be more denser in order to have equal landmass.

Mars should be more denser, if it has equal landmass.

But in reality, it's landmass is not equal 'cause it's density is about 72% of that of earth.

Hope this helps!
4 0
3 years ago
M<br> An object has a mass of 5.52 g and a volume of 12 mL. What is the density of the object
shutvik [7]

Answer:

0.46 g/mL

Explanation:

Density can be found using the following formula.

d=\frac{m}{v}

where <em>d</em> is density, <em>m</em> is mass, and <em>v</em> is volume.

We know that the object has a mass of 5.52 grams and a volume of 12 milliliters.

m=5.52 g

v=12 mL

Substitute these values into the formula.

d=\frac{5.52 g}{12 mL}

Divide 5.52 by 12

5.52/12=0.46

d=0.46 g/mL

The density of the object is 0.46 g/mL, and option C is correct.

4 0
3 years ago
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