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Anni [7]
3 years ago
7

Difference between regular and irregular object.​

Physics
1 answer:
DaniilM [7]3 years ago
5 0
<h2><em>Answer:</em></h2><h2><em>Regular </em><em>object</em></h2>
  • <em>Those </em><em>substance </em><em>which </em><em>have </em><em>fixed </em><em>geometrical </em><em>shape </em><em>are </em><em>called </em><em>regular </em><em>object.</em>
  • <em>For </em><em>example</em><em>:</em><em> </em><em>books,</em><em>pencils,</em><em> </em><em>basketball</em><em> </em><em>etc.</em>
<h2><em>Irregular </em><em>object</em></h2>
  • <em>Those </em><em>substance </em><em>which </em><em>do </em><em>not </em><em>have </em><em>geometrical</em><em> </em><em>shape </em><em>are </em><em>called </em><em>irregular</em><em> </em><em>object</em><em>.</em>
  • <em>For </em><em>example:</em><em> </em><em>a </em><em>piece </em><em>of </em><em>stone,</em><em>a </em><em>broken </em><em>piece </em><em>of </em><em>brick,</em><em>leaf </em><em>etc.</em>

<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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Westkost [7]

Answer:

Final velocity, v = 0.28 m/s

Explanation:

Given that,

Mass of the model, m_1=0.205\ kg

Speed of the model, u_1=0.72\ m/s

Mass of another model, m_2=0.32\ kg

Initial speed of another model, u_2=0

To find,

Final velocity

Solution,

Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :

m_1u_1+m_2u_2=(m_1+m_2)V

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

V=\dfrac{0.205\times 0.72+0.32\times 0}{(0.205+0.32)}

V = 0.28 m/s

So, their final velocity is 0.28 m/s. Hence, this is the required solution.

6 0
3 years ago
Suppose a door is 1 meter wide. Calculate the difference in the amount torque exerted on the door when someone pushes with a con
Yanka [14]

Answer:

Δτ = 50 N.m

Explanation:

The torque applied on an object is given by the product of the force applied on it and the perpendicular distance between the force and the axis of rotation of the object. That is:

τ = F r

where,

τ = Torque applied on the object

F = Force applied on it

r = distance from axis of rotation

<u>FOR HANDLE SIDE OF DOOR</u>:

τ₁ = F r₁

where,

τ₁ = Torque applied on the object = ?

F = Force applied on it = 100 N

r₁ = distance from axis of rotation = 1 m

Therefore,

τ₁ = (100 N)(1 m)

τ₁ = 100 N.m

<u></u>

<u>FOR MIDDLE OF DOOR</u>:

τ₂ = F r₂

where,

τ₂ = Torque applied on the object = ?

F = Force applied on it = 100 N

r₂ = distance from axis of rotation = 1 m/2 = 0.5 m

Therefore,

τ₂ = (100 N)(0.5 m)

τ₂ = 50 N.m

Now, the difference between the amount of torque in both cases is:

Δτ = τ₁ - τ₂

Δτ = 100 N.m - 50 N.m

<u>Δτ = 50 N.m</u>

6 0
3 years ago
Does anyone know this? How far does it travel?
erik [133]
U=5.82,a=2.35,t=3.25

s=u*t+ \frac{1}{2}*a* t^{2}

just substitute.
5 0
3 years ago
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Answer:

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Explanation:

4 0
4 years ago
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Luba_88 [7]

Answer:

c is correct

Explanation:

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Which of the following terms BEST describes steel? homogeneous mixture

3 0
3 years ago
Read 2 more answers
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