Answer:
603??? But I have no idea so don’t type this in
X1= -3/2
X2= 0
F(x)=4x^2+6x
To find X-intercept/zero, substitute f(x)=0
0=4x^2+6x
Move the constant to the right
4x^2+6x=0
Factor out 2x from the expression
2x(2x+3)=0
Divide both sides of the equation
2x(2x+3)/2=0/2
X(2x+3)=0
When the product of factors equals 0, at least one factor is 0.
X=0
2x+3=0
Next you solve for X by moving the constant to the right
2x=-3
Then divide both sides by 2
X=-3/2
Hope this answers your question.
9514 1404 393
Answer:
- x=2 (work is correct)
- x=4
- x=44
- x=4
- x=any number
- impossible; no such number
Step-by-step explanation:
1. The equation is ...
3x +5 = 11
3x = 11 -5 = 6
x = 6/3 = 2 . . . . matches the work shown
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2. The equation is ...
(x +2)·5 = 30
x +2 = 30/5 = 6
x = 6 -2 = 4
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3. The equation is ...
(x/2) +2 = 24 . . . . matches the work shown
x/2 = 24 -2 = 22
x = 22·2 = 44
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4. The equation is ...
2x +8 = x +12
2x = x + 12 -8 = x +4
2x -x = x -x +4
x = 4
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5. The equation is ...
2x +4 -x -3 = x +1
x +1 = x +1 . . . . . true for any value of x
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6. The equation is ...
(3x +6) -2x = x +3
x +6 = x +3 . . . . . not true for any number
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<em>Additional comment</em>
The work shown is correct. You find x by writing and solving an appropriate equation. To solve the equation, undo the steps that are done to x. Undo addition by adding the opposite. Undo multiplication by diving by the multiplier. It often helps to collect terms before you start the "undo" steps.
For x on both sides of the equation (as in problems 4–6), you can subtract the term with the lowest coefficient. (Of course, you must subtract it from both sides of the equation.) In problem 5, if you do that, you get 1=1, which is true for any value of x. In problem 6, if you do that, you get 6=3, a false equation, indicating no value of x will make it true.
20 or 550 tickets were sold to the Spring Fling dance.
6x[7+(15-8)]divided by 3=28 hope this helps