4141% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that t
1 answer:
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Answer:
(1) 97
(2) 385
(3) 9604
Step-by-step explanation:
The (1 - <em>α</em>) % confidence interval for population proportion is:
The margin of error in this interval is:
The formula to compute the sample size is:
(1)
Given:
*Use the <em>z</em>-table for the critical value.
Compute the value of <em>n</em> as follows:
Thus, the minimum sample size required is 97.
(2)
Given:
*Use the <em>z</em>-table for the critical value.
Compute the value of <em>n</em> as follows:
Thus, the minimum sample size required is 385.
(3)
Given:
*Use the <em>z</em>-table for the critical value.
Compute the value of <em>n</em> as follows:
Thus, the minimum sample size required is 9604.
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