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wariber [46]
3 years ago
12

Give the scale factor of Figure B to Figure A.

Mathematics
1 answer:
uysha [10]3 years ago
6 0

The figures are similar.

the side that is 16 on A is similar to the side that measures 4 on figure B

24 is similar to 6

32 is similar to 8

24 is 4 times 6

24 / 6 = 4

32 is 4 times 8

32 / 4 = 4

and 16 is 4 times  4

16 /4 =4

Figure A is 4 times bigger than Figure B. That is your scale factor.

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Natali5045456 [20]

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Answer:

A. y=3x-10

C. y+6=3(x-15)

Step-by-step explanation:

Given:

The given line is 6x+18y=5

Express this in slope-intercept form y=mx+b, where m is the slope and b is the y-intercept.

6x+18y=5\\18y=-6x+5\\y=-\frac{6}{18}x+\frac{5}{18}\\y=-\frac{1}{3}x+\frac{5}{18}

Therefore, the slope of the line is m=-\frac{1}{3}.

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Let us find the slopes of each lines.

Option A:

y=3x-10

On comparing with the slope-intercept form, we get slope as  m_{A}=3.

Now, m\times m_{A}=-\frac{1}{3}\times 3=-1. So, option A is perpendicular to the given line.

Option B:

For lines of the form x=a, where, a is a constant, the slope is undefined. So, option B is incorrect.

Option C:

On comparing with the slope-point form, we get slope as  m_{C}=3.

Now, m\times m_{C}=-\frac{1}{3}\times 3=-1. So, option C is perpendicular to the given line.

Option D:

3x+9y=8\\9y=-3x+8\\y=-\frac{3}{9}x+\frac{8}{9}\\y=-\frac{1}{3}x+\frac{8}{9}

On comparing with the slope-intercept form, we get slope as  m_{D}=-\frac{1}{3}.

Now, m\times m_{D}=-\frac{1}{3}\times -\frac{1}{3}=\frac{1}{9}. So, option D is not perpendicular to the given line.

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3 years ago
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