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3 years ago

Need help with this question please

Mathematics

1 answer:

zhenek [66]3 years ago

8 0

Answer:

idk why it is not letting my see your pic

Step-by-step explanation:

sorry with i could help good luck

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Which is one is correct?

SVEN [57.7K]

Answer:

the 3rd number line

Step-by-step explanation:

first of all, we know That the line starts from zero.

the inequation is n>0

the circle inside should be the hallow one because it's "greater" not greater than or equal to.

n>0 means that n is greater than 0.

in the number line, ( the 3rd one) n is going away from 0. it's going greater than 0.

that is why this is the correct answer.

I hope this clarified any confusion.

3 0

3 years ago

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What is the range of this graph?

ozzi

Answer:

Step-by-step explanation: Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis.

5 0

3 years ago

Y=-x^2+6x-4 Find the Axis of Symmetry and the Vertex, Also solve the whole equation.

Inessa [10]

Answer:

1. Axis of symmetry: x = 3

2. Vertex: (3,5)

3. Solution of the equation:

x-intercepts:

$(3-\sqrt{5},0) \\\\(3+\sqrt{5},0)$

y-intercept: (0, -4)

Explanation:

1. Equation:

$y=-x^2+6x-4$

2. Axis of symmetry:

That is the equation of a parabola, whose standard form is:

$y=ax^2+bx+c$

Where:

$a=-1;b=6;c=-4$

The axis of symmetry is the vertical line with equation:

$x=-b/2a$

Substitute $a=-1,\text{ and }b=6$

$x=-6/[(2)(-1)]=-6/(-2)=3$

Thus, the axis of symmetry is:

$x=3$

3. Vertex

The x-coordinate of the vertex is equal to the axys of symmetry, i.e x = 3.

To find the y-xoordinate, substitute this value of x into the equation for y:

$y=-x^2+6x-4\\\\y=-(3)^2+6(3)-4=-9+18-4=5$

Therefore, the vertex is (3, 5)

4. Find the x-intercepts

The x-intercepts are the roots of the equation, which are the points wher y = 0.

$y=-x^2+6x-4=0$

Use the quadratic equation:

$x=\frac{-b\pm \sqrt{b^2-4ac} }{2a} \\\\x=\frac{-6\pm\sqrt{(-6)^2-4(-1)(-4)} }{2(-1)}\\\\x_1=3-\sqrt{5} \\\\x_2=3+\sqrt{5}$

5. Find the y-intercept

The y-intercet is the value of y when x=0:

$y=-x^2+6x-4\\\\y=-(0)^2+6(0)-4=-4$

7 0

3 years ago

How to do a exponent with the negative base?

tatiyna

Examples :
(-2)^3 = (-2)(-2)(-2) = - 8

(-3)^4 = (-3)(-3)(-3)(-3) = 81

(-1)^5 = (-1)(-1)(-1)(-1)(-1) = -1

** if the exponent is an even number, the answer will be positive. if the exponent is an odd number, then the answer will be negative

** but keep in mind....if the negative is not included with the base..
-(5^2) = - 25....but (-5^2) = 25

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3 years ago

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How long is a school bus

Sonja [21]

Answer:

45 ft

Step-by-step explanation:

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