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3 years ago

15

Need help with this question please

1 answer:

zhenek [66]3 years ago

8 0

Answer:

idk why it is not letting my see your pic

Step-by-step explanation:

sorry with i could help good luck

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Meghan also wants to walk to get some exercise, rather than going to the gym. She decides to walk along arc AB. How far will she

Karo-lina-s [1.5K]

Answer:

π*AB

Step-by-step explanation:

I m not quite sure about your question because it is lack of details.

However, as my per understanding, Meghan decides to walk along arc AB it means she walks an interval equal to the circumference of the circle AB.

So, apply the formula in caculating the circumference of the circle, we have:

π*d = π*AB

So, she walk a π*AB distance.

8 0

4 years ago

(ii) A peacock is sitting on the tree and observes its prey on

Paraphin [41]

Answer:

74.8 m

Step-by-step explanation:

We are given that

$\theta=22^{\circ}$

Speed of peacock,v=10 km/h

Time,t=1 min 12 sec=60+12=72 s= $\frac{72}{3600}=0.02 h$

1 hour=3600 s

Distance=vt= $10\times 0.02=0.2 km=0.2\times 1000=200 m$

Using 1 km=1000 m

We know that

$sin\theta=\frac{Perpendicular\;side}{hypotenuse}$

Using the formula

$sin22=\frac{h}{200}$

$h=200sin22=200\times 0.374=74.8 m$

Hence, the peacock was at height of 74.8 m on the tree.

3 0

3 years ago

Please help me ASAP!!!

RoseWind [281]

Answer:

C

Step-by-step explanation:

0 is closed 8 is open

4 0

3 years ago

suppose for an angle theta in a right triangle cos theta = C. Sketch and label this triangle, and then use it to write the other

VARVARA [1.3K]

Answer:

$sin\theta = \sqrt{1-C^2}$

$tan\theta = \dfrac{\sqrt{1-C^2}}{C}$

$cot\theta = \dfrac{C}{\sqrt{1-C^2}}$

$sec\theta = \dfrac{1}{C}}$

$cosec\theta = \dfrac{1}{\sqrt{1-C^2}}$

Step-by-step explanation:

Given that:

$\theta$ is an angle in a right angled triangle.

and $cos\theta = C$

To find:

To draw the triangle and write other five trigonometric functions in terms of C.

Solution:

We know that cosine of an angle is given by the formula:

$cosx =\dfrac{Base}{Hypotenuse}$

Here, we are given that $cos\theta = C$ OR

$cos\theta = \dfrac{C}{1}$

i.e. Base = C and Hypotenuse of triangle = 1

Please refer to the right angled triangle as per given statements.

$\triangle PQR$ , with base PR = C units

and hypotenuse, QP = 1 unit

$\angle R$ is the right angle.

Let us use pythagorean theorem to find the value of perpendicular.

According to pythagorean theorem:

$\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}$

$1^{2} = C^{2} + QR^{2}\\\Rightarrow QR = \sqrt {1-C^2}$

$sin\theta = \dfrac{Perpendicular}{Hypotenuse}\\\Rightarrow sin\theta = \dfrac{\sqrt{1-C^2}}{1}\\\Rightarrow sin\theta = \sqrt{1-C^2}$

$tan\theta = \dfrac{Perpendicular}{Base}\\\Rightarrow tan\theta = \dfrac{\sqrt{1-C^2}}{C}$

$cot\theta = \dfrac{Base}{Perpendicular}\\\Rightarrow cot\theta = \dfrac{C}{\sqrt{1-C^2}}$

$sec\theta = \dfrac{Hypotenuse}{Base}\\\Rightarrow sec\theta = \dfrac{1}{C}}$

$cosec\theta = \dfrac{Hypotenuse}{Perpendicular}\\\Rightarrow cosec\theta = \dfrac{1}{\sqrt{1-C^2}}$

5 0

3 years ago

The complement of an angle is 25°. What is the measure of the angle?

Varvara68 [4.7K]

65 degrees.

90 - 25 = 65

3 0

4 years ago