Answer:
1.67×10^-11 N
Explanation:
m1 = 0.13kg
m2 = 0.34kg
d = 0.42m
G = 6.674 × 10 ^−11
F = Gm1m2/r²
F= (6.674 × 10^ −11×0.13×0.34)/(0.42)²
F = 1.67×10^-11 N
The stiffness constant of the spring is 68,290.3 N/m
<h3>
Stiffness constant of the spring</h3>
Apply the principle of conservation of energy;
U = K.E
¹/₂kx² = ¹/₂mv²
kx² = mv²
k = mv²/x²
where;
- v is speed = 60 km/h = 16.67 m/s
- x is the distance
k = (1300 x 16.67²)/(2.3²)
k = 68,290.3 N/m
Thus, the stiffness constant of the spring is 68,290.3 N/m.
Learn more about stiffness constant here: brainly.com/question/1685393
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I'm pretty sure it's Protons