Question

A 1300-kg car moving on a horizontal surface has speed v = 60 km/h when it strikes a horizontal coiled spring and is brought to rest in a distance of 2.3 m .
What is the spring stiffness constant of the spring?
Express your answer to two significant figures and include the appropriate units.

Answer 1

The stiffness constant of the spring is 68,290.3 N/m

Stiffness constant of the spring

Apply the principle of conservation of energy;

U = K.E

¹/₂kx² = ¹/₂mv²

kx² = mv²

k = mv²/x²

where;

• m is mass

• v is speed = 60 km/h = 16.67 m/s
• x is the distance

k = (1300 x 16.67²)/(2.3²)

k = 68,290.3 N/m

Thus, the stiffness constant of the spring is 68,290.3 N/m.

Learn more about stiffness constant here: brainly.com/question/1685393

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