Answer:
0.465 kgm/s
Explanation:
Given that
Mass of the cart A, m1 = 450 g
Speed of the cart A, v1 = 0.85 m/s
Mass of the cart B, m2 = 300 g
Speed of the cart B, v2 = 1.12 m/s
Now, using the law of conservation of momentum.
It is worthy of note that our cart B is moving in opposite directions to A
m1v1 + m2v2 =
(450 * 0.85) - (300 * 1.12) =
382.5 - 336 =
46.5 gm/s
If we convert to kg, we have
46.5 / 100 = 0.465 kgm/s
Thus, the total momentum of the system is 0.465 kgm/s
M = 4kg
F =8N
a..?
F =m.a
8 = 4.a
a = 2m/s^2
A law has always been observed to be true
Answer:v
Explanation:
Given
Initially spring mass system is moving towards right with velocity 
Now if the spring is released left block moves towards left with a velocity 
As there is no external force applied on the system therefore the change in linear momentum is zero i.e. it is conserved
so center of mass continue to move towards the right with velocity v or we can say right block moves towards right with velocity
and left block moves with velocity 