All categories

3 years ago

Rectangle PQRS has vertices at P(3,5), Q(8,5), R(8,0) and S. The coordinates of point S are

Mathematics

2 answers:

pashok25 [27]3 years ago

7 0

I would have guessed point S is (3,0).

const2013 [10]3 years ago

5 0

The answer is (-3,0)

I hope this helps. :)

You might be interested in

ryzh [129]

Answer:

(1 ) Inner curved surface area of the well is 109.9 sq. meters.

(2) The cost of plastering the total curved surface area is 4396.

Step-by-step explanation:

The inner diameter = 3.5 m

Depth of the well = 10 m

Now, Diameter = 2 x Radius

⇒R = D/ 2 = 3.5/2 = 1.75

or, the inner radius of the well = 1.75 m

CURVED SURFACE AREA of cylinder = 2πr h

⇒The inner curved surface area = 2πr h = 2 ( 3.14) (1.75)(10)

= 109 sq. meters

Hence, the inner curved surface area of the well is 109.9 sq. meters.

Now, the cost of plastering the curved area is 40 per sq meters

So, the cost of total plastering total area = 109.9 x(Cost per meter sq.)

= 109.9 x (40)

= 4396

Hence, the cost of plastering the total curved surface area is 4396.

8 0

3 years ago

Simplify and write in standard form (7-8i)(7-8i)<br><br>plzzzz show all work<br>

ASHA 777 [7]

7-(8*7)+(8*6)+(8*5)+(8*4)+(8*3)+(8*2)+(8*1)=7-56+48+40+32+24+16+8= 217*217= 47089

7 0

2 years ago

The altitude of a triangle is increasing at a rate of 1.5 1.5 centimeters/minute while the area of the triangle is increasing at

seraphim [82]

Answer:

The base reduces at 3.75cm/min

Step-by-step explanation:

Given

Let

$h \to altitude$

$b \to base$

$A \to Area$

So:

$\frac{dh}{dt} = 1.5cm/min$

$\frac{dA}{dt} = 1.5^2cm/min$

The area of a triangle is:

$A = \frac{1}{2}bh$

Calculate b when $A =88cm^2; h =8cm$

$A = \frac{1}{2}bh$

$88=\frac{1}{2} * b * 8$

$88 =b * 4$

Solve for b

$b = 88/4$

$b = 22$

We have:

$A = \frac{1}{2}bh$

Differentiate with respect to time

$\frac{dA}{dt} =\frac{1}{2}(h\frac{db}{dt} + b\frac{dh}{dt})$

Substitute the following values in the above equation

$\frac{dh}{dt} = 1.5cm/min$ $\frac{dA}{dt} = 1.5^2cm/min$ $b = 22$ $h = 8$

$1.5 = \frac{1}{2}(8 * \frac{db}{dt} + 22 * 1.5)$

Multiply both sides by 2

$3 = 8 * \frac{db}{dt} + 22 * 1.5$

$3 = 8 * \frac{db}{dt} + 33$

Collect like terms

$8 * \frac{db}{dt} = 3 -33$

$8 * \frac{db}{dt} = -30$

Divide both sides by 8

$\frac{db}{dt} = -\frac{30}{8}$

$\frac{db}{dt} = -3.75$

4 0

3 years ago

If f(x) = 3x - 2 and g(x) = 2x + 1, find (f+g)(x).

jeka57 [31]

Answer:

Step-by-step explanation:

(f + g)(x) = f(x) + g(x)

f(x) + g(x)

= 3x - 2 + 2x + 1 ← collect loke terms

= 5x - 1 → A

5 0

3 years ago

2. Define the absolute value function, y = |x|, as a piecewise function. Please include complete sentences and examples to justi

Mekhanik [1.2K]

Y = |x| = x if x ≥ 0, -x if x < 0

absolute value can be interpreted as a function that does not allow negative real numbers, forcing them to be positive (leaving 0 alone). if the input x is more than or equal 0, then x stays positive so there is no need to do anything: "x if x ≥ 0".
if the input is less than 0, then it is an negative number and needs a negative coefficient to negate the negative: "-x if x < 0"

example: if x = -3, then it will take the "-x if x < 0" piece resulting in y = -(-3) = 3, which is what |-3| does

if x = 1, it will take the "x if x ≥ 0" piece and just have y = 1 which is what |1| does.

for x = 0, it will take the "x if x ≥ 0" and just have y = 0 which is what |0| does

7 0

3 years ago