In this case, we have to keep in mind that in the monosubstituted product we only have to replace 1 hydrogen with another group. In this case, we are going to use the methyl group $CH_3$ .

In the axial position, we have a more steric hindrance because we have two hydrogens near to the $CH_3$ group. If we have more steric hindrance the molecule would be more unstable. In the equatorial positions, we don't any interactions because the $CH_3$ group is pointing out. If we don't have any steric hindrance the molecule will be more stable, that's why the molecule will the equatorial position.

See figure 1

I hope it helps!

6 0

2 years ago

Find the molarity of 750 ml solution containing 346 g of potassium nitrate

Zinaida [17]

Given mass of KNO₃=346g
Molar mass of KNO₃=(39.098)+(14)+(15.99*3)=101.068gmol⁻¹
Volume of Solution=750ml=0.75dm³

Molarity=(mass of solute/molar mass of solute)*(1/volume of sol. in dm³)
=(346/101.068)*(1/0.75)
=4.56 mol dm⁻³

5 0

3 years ago

21,980 mg of phosphorus reacts in a gas jar containing oxygen. The resulting oxide weighed 50.000 g. The percent composition of

stealth61 [152]

Answer: False

Explanation:

8 0

3 years ago

Bromine has chemical properties most similar to...

Aleksandr-060686 [28]

Flourine.

You are very welcome

3 0

3 years ago

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