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grin007 [14]
3 years ago
5

When a chemical reaction reaches chemical equilibrium which occurs faster, the formation of product from reactants or reactants

from product?
Chemistry
1 answer:
nekit [7.7K]3 years ago
4 0

Answer: when a system reaches equilibrium, the rate of formation of product equals the rate of formation of reactant. At this state, we say the reaction is in dynamic equilibrium. Therefore the rate of formation of product and the rate of formation of reactant are equal

Explanation:

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What state of matter has a definite shape and volume.
anastassius [24]

Solids have a definite shape and volume. They are always the same shape no matter what they are contained in; their volume is also the same because they don't change unless you add or take away from it.

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Liquids have an indefinite shape but definite volume. They expand to fill out the space they are contained in, but their volume doesn't change unless you take out or add more of the liquid.

Gases have an indefinite shape and volume. Gases expand to fill out the space they are in and also don't have a clear shape because they are not always in one form.

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What happens to the temperature of the remaining liquid when some of the liquid evaporates
Dovator [93]
Turns into vapor. not all of the molecules are liquid have the same energy
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When the cations Na+, K+, Rb+, Cs+ are combined with chloride ion in the gas phase to form ion pairs, which pair formation relea
Gemiola [76]

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NaCl

Explanation:

5 0
3 years ago
Read 2 more answers
What is the MOLAR heat of combustion of methane(CH₄) if 64.00g of methane are burned to heat 75.0 ml of water from 25.00°C to 95
melamori03 [73]

Answer:

-5.51 kJ/mol

Explanation:

Step 1: Calculate the heat required to heat the water.

We use the following expression.

Q = c \times m \times \Delta T

where,

  • c: specific heat capacity
  • m: mass
  • ΔT: change in the temperature

The average density of water is 1 g/mL, so 75.0 mL ≅ 75.0 g.

Q = 4.184J/g.\°C \times 75.0g \times (95.00\°C - 25.00\°C) = 2.20 \times 10^{3} J = 2.20 kJ

Step 2: Calculate the heat released by the methane

According to the law of conservation of energy, the sum of the heat released by the combustion of methane (Qc) and the heat absorbed by the water (Qw) is zero

Qc + Qw = 0

Qc = -Qw = -22.0 kJ

Step 3: Calculate the molar heat of combustion of methane.

The molar mass of methane is 16.04 g/mol. We use this data to find the molar heat of combustion of methane, considering that 22.0 kJ are released by the combustion of 64.00 g of methane.

\frac{-22.0kJ}{64.00g} \times \frac{16.04g}{mol} = -5.51 kJ/mol

8 0
3 years ago
How many molecules of copper sulfate are needed to produce 5.0×1024 molecules of sodium sulfate?
lubasha [3.4K]

Answer:

5.0 × 10²⁴ molecules

Explanation:

Step 1: Write the balanced double displacement reaction

2 NaOH + CuSO₄ ⇒ Na₂SO₄ + Cu(OH)₂

Step 2: Calculate the moles corresponding to 5.0 × 10²⁴ molecules of Na₂SO₄

We will use Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.

5.0 × 10²⁴ molecule × 1 mol/6.02 × 10²³ molecule = 8.3 mol

Step 3: Calculate the moles of CuSO₄ required to produce 8.3 moles of Na₂SO₄

The molar ratio of CuSO₄ to Na₂SO₄ is 1:1. The moles of CuSO₄ required are 1/1 × 8.3 mol = 8.3 mol.

Step 4: Calculate the molecules corresponding to 8.3 moles of CuSO₄

We will use Avogadro's number.

8.3 mol × 6.02 × 10²³ molecule/1 mol = 5.0 × 10²⁴ molecule

4 0
3 years ago
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