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2 years ago

How do you identify short and long term comets

1 answer:

8 0

A second important difference between comets coming from the Kuiper Belt and from the Oort cloud is represented by their different characteristic periods.
In fact, short period comets are thought to generate in the Kuiper belt and have rather predictable orbits with short periods (up to 200 years). There are two major families of short period comets: the Jupiter family with periods of less than 20 years and the Halley family with periods form 20 to 200 years. That's short

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State two factors that affect the spring constant of a spring made using a wire of a certain material and given thickness

MaRussiya [10]

The spring's rigidity is quantified by the spring constant. The spring constant increases as the wire's thickness increases. The spring constant lowers as the coil's diameter increases.

Material: Steel and copper are two materials that have differing constants when used to make identical springs.

Describe the spring constant ?

The restoring force applied to the spring for a given length of deflection is known as the spring constant. It is often referred to as the amount of force needed to extend or compress a spring one unit of length.

The level of resistance to spring deformation is expressed by the spring constant. In addition to being known as spring stiffness or spring rate, the spring constant and It is represented by the letter "K."

The following variables affect the coil spring's spring constant:-

a) Modulus of rigidity (G): As the modulus of rigidity of the spring material increases, so does the coil spring's spring constant.

b) Wire diameter (d): As the diameter of the spring wire grows, so does the spring constant.

c) Coil diameter (D): As the diameter of the spring coil increases, so does the spring's spring constant.

d) Number of coils (n): As the number of spring coils increases, the spring constant decreases.

To know more about spring constant :

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8 0

1 year ago

Suppose that you wanted to close a door by throwing a ball at the door. one ball will bounce off the door in a perfectly elastic

Wewaii [24]

The perfect elastic Collision ball will hit the door first because the clay is heavier and will take more time

5 0

3 years ago

Desde lo alto de un acantilado de 140 m, se lanza verticalmente un objeto hacia abajo con velocidad de 3m/s. Entonces la magnitu

grin007 [14]

Answer:

Explanation:

d = vo*t + ½*g*t²

d = 3*3 + ½*10*3²

d = 9 + 45

d = 54 m

entonces el objeto tiene 54 m de desplazamiento

7 0

2 years ago

Michelle recently started selling her invention: A bed that looks like it floats in mid-air. The bed is actually suspended by ma

Tamiku [17]

Answer:

Explanation:

designer

illusionist

engineer

entrepreneur

salesperson

human

inventor

8 0

2 years ago

In a carrom game, a striker weighs three times the mass of the other pieces, the carrom men and the queen, which each have a mas

Mila [183]

Answer:

- The final velocity of the queen is (3/2) of the initial velocity of the striker. That is, (3V/2)

- The final velocity of the striker is (1/2) of the initial velocity of the striker. That is, (V/2)

Hence, the relative velocity of the queen with respect to the striker after collision

= (3V/2) - (V/2)

= V m/s.

Explanation:

This is a conservation of Momentum problem.

Momentum before collision = Momentum after collision.

The mass of the striker = M

Initial Velocity of the striker = V (+x-axis)

Let the final velocity of the striker be u

Mass of the queen = (M/3)

Initial velocity of the queen = 0 (since the queen was initially at rest)

Final velocity of the queen be v

Collision is elastic, So, momentum and kinetic energy are conserved.

Momentum before collision = (M)(V) + 0 = (MV) kgm/s

Momentum after collision = (M)(u) + (M/3)(v) = Mu + (Mv/3)

Momentum before collision = Momentum after collision.

MV = Mu + (Mv/3)

V = u + (v/3)

u = V - (v/3) (eqn 1)

Kinetic energy balance

Kinetic energy before collision = (1/2)(M)(V²) = (MV²/2)

Kinetic energy after collision = (1/2)(M)(u²) + (1/2)(M/3)(v²) = (Mu²/2) + (Mv²/6)

Kinetic energy before collision = Kinetic energy after collision

(MV²/2) = (Mu²/2) + (Mv²/6)

V² = u² + (v²/3) (eqn 2)

Recall eqn 1, u = V - (v/3); eqn 2 becomes

V² = [V - (v/3)]² + (v²/3)

V² = V² - (2Vv/3) + (v²/9) + (v²/3)

(4v²/9) = (2Vv/3)

v² = (2Vv/3) × (9/4)

v² = (3Vv/2)

v = (3V/2)

Hence, the final velocity of the queen is (3/2) of the initial velocity of the striker and is in the same direction.

The final velocity of the striker after collision

= u = V - (v/3) = V - (V/2) = (V/2)

The relative velocity of the queen withrespect to the striker after collision

= (velocity of queen after collision) - (velocity of striker after collision)

= v - u

= (3V/2) - (V/2) = V m/s.

Hope this Helps!!!!

3 0

3 years ago

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