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3 years ago

6

Which wavelengths of light drive the highest rates of photosynthesis?

1 answer:

wariber [46]3 years ago

3 0

Answer:

400-450 nm and 670-680 nm

Explanation:

Which wavelengths of light drive the highest rates of photosynthesis?

400-450 nm and 670-680 nm

Light in the violet-blue and red portions of the spectrum is most effective in driving photosynthesis

photosynthesis is the process through which green plant manufacture there food through sunlight, they synthesize nutrient in the this process through chlorophyll thereby releasing oxygen as a bye-product. a spectrum contains 7 colours combined . the violet-blue and red portions of the spectrum is most effective

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A train travels 92 miles in 11 1/2 hours. what is its average speed in miles per hour?

Gnom [1K]

The answer is 8 mph.

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2 years ago

the average speed of a runner in a 483. meter race is 3.0 meters per second. How long me runner to complete the race? Dont inclu

lara [203]

Answer:

161

Explanation:

$v=\frac{d}{t}$ slove for t

$t=\frac{d}{v}$

Insert values of d and v

$t=\frac{483}{3} \\$

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2 years ago

Unpolarized light passes through two polarizers whose transmission axes are at an angle # with respect to each other. What shoul

Yuki888 [10]

Answer:

$63.4^{\circ}$

Explanation:

When unpolarized light passes through the first polarizer, the intensity of the light is reduced by a factor 1/2, so

$I_1 = \frac{1}{2}I_0$ (1)

where I_0 is the intensity of the initial unpolarized light, while I_1 is the intensity of the polarized light coming out from the first filter. Light that comes out from the first polarizer is also polarized, in the same direction as the axis of the first polarizer.

When the (now polarized) light hits the second polarizer, whose axis of polarization is rotated by an angle $\theta$ with respect to the first one, the intensity of the light coming out is

$I_2 = I_1 cos^2 \theta$ (2)

If we combine (1) and (2) together,

$I_2 = \frac{1}{2}I_0 cos^2 \theta$ (3)

We want the final intensity to be 1/10 the initial intensity, so

$I_2 = \frac{1}{10}I_0$

So we can rewrite (3) as

$\frac{1}{10}I_0 = \frac{1}{2}I_0 cos^2 \theta$

From which we find

$cos^2 \theta = \frac{1}{5}$

$cos \theta = \frac{1}{\sqrt{5}}$

$\theta=cos^{-1}(\frac{1}{\sqrt{5}})=63.4^{\circ}$

6 0

2 years ago

Some people wish that we lived in a recollapsing universe that would eventually stop expanding and start contracting. For this t

Monica [59]

Answer:

(B) Dark energy does not exist and there is much more matter than current evidence suggests.

Explanation:

The repulsive force which is accelerating expansion of the universe is called as dark energy. Most of matter present in the universe is the dark matter of about eighty five percent.

So, a collapsing universe would not have the dark energy and there is more matter which is not the dark matter. This theory is rejected because expansion of the universe is observable.

4 0

3 years ago

(TCO 5) The relationship between Celsius (º C) and Fahrenheit (º F) degree of measuring temperature is linear. Find the linear e

gtnhenbr [62]

Answer:

$C=-\dfrac{10}{17}(F-32)$

Explanation:

Given that

32° F corresponds to 0 °C. ---Point 1

212° F corresponds to 100 °C.----Point 2

We know that if two point is given that equation of line can be found as

$y-y_1=\dfrac{y_2-y_1}{x_2-x_2}(x-x_1)$

Lets C in y- direction and F in x- direction,so we can say that

$C-C_1=\dfrac{C_2-C_1}{F_2-F_2}(F-F_1)$

$C-0=\dfrac{100-0}{32-212}(F-32)$

$C=-\dfrac{10}{17}(F-32)$

So the linear relationship is

$C=-\dfrac{10}{17}(F-32)$

8 0

3 years ago