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GrogVix [38]
3 years ago
11

The scale on the horizontal line axis is 5s per division on the vertical axis 9 m per division

Physics
1 answer:
andrew11 [14]3 years ago
5 0

Questions deserve answers in their common format.

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Using the equation for for Newton's Second law, m=F/a solve the following problem. You have been given an object with a force of
inessss [21]

Answer:

4. 5g

Explanation:

F=ma so, m=Fa. All you have to do is 10/2. Don't be confused by the units. Mass will normally be in grams.

8 0
3 years ago
A light wave travels through water (n=1.33) at an angle of 35º. What angle
san4es73 [151]

Answer:

49.7^{\circ}

Explanation:

We can solve the problem by using Snell's law:

n_1 sin \theta_1 = n_2 sin \theta_2

where

n1 = 1.33 is the index of refraction of the first medium (water)

n2 = 1.00 is the index of refraction of the second medium (air)

\theta_1 = 35^{\circ} is the angle of incidence of the wave in water

\theta_2 is the angle of refraction of the wave in air

Solving for the angle of refraction,

sin \theta_2 = \frac{n_1 sin \theta_1}{n_2}=\frac{(1.33) sin 35^{\circ}}{1.00}=0.763\\\theta_2 = sin^{-1} (0.763)=49.7^{\circ}

6 0
3 years ago
Read 2 more answers
Find the work w1 done on the block by the force of magnitude f1 = 75.0 n as the block moves from xi = -1.00 cm to xf = 3.00 cm .
MissTica
<span>The work done is 3.0 Nm. We can us the equation Work = Force * Distance, where Force = 75.0 N, and distance is xf – xi = 3.00 cm - -1.00 cm = 4.00 cm. Convert centimeters to meters by moving the decimal place to the left by two places to get 0.04 m. Plug these values into the Work equation: Work = Force * Distance Work = 75.0 N * 0.04 m Work = 3.0 Nm</span>
5 0
3 years ago
Violet light has a frequency of 7.26 × 1014 Hz and travels at a speed of 3.00 × 108 m/s.
Anuta_ua [19.1K]

Answer:

what's the question

........

8 0
2 years ago
David is driving a steady 28.0 m/s when he passes Tina, who is sitting in her car at rest. Tina begins to accelerate at a steady
rodikova [14]

Answer:

Explanation:

Let t represent the time for Tina to catch David.

Hence, considering the equation of linear motion S = ut + 1/2at^2..... 1

For David u = 28.0 m/s where 'a' is set to nought

S = ut

S = 28t.......2

For Tina consider equation 1

Where acceleration = 2.90m/s^2 and u is set at nought

S = 1/2×2.90 m/s×t^2.......3

Equate 2 and 3

28t = 1.45t^2

Divide through by t

28 = 1.45t

t = 28/1.45

t = 19.31seconds

Now put the value of t into equation 3

S = 1/2×2.90 m/s×t^2.......3

= 1.45×20×20

= 580m

Tina must have driven 580meters before passing David

Considering the equation of linear motion : V^2 = U^2+2as

Where u is set at nought

V^2 = 2as

V^2 = 2×2.9×580

V^2 = 3364

V = √3364

V = 58m/s

Her speed will be 58m/s

7 0
3 years ago
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