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GrogVix [38]
2 years ago
11

The scale on the horizontal line axis is 5s per division on the vertical axis 9 m per division

Physics
1 answer:
andrew11 [14]2 years ago
5 0

Questions deserve answers in their common format.

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A force of 1.150×103 N pushes a man on a bicycle forward. Air resistance pushes against him with a force of 795 N. If he starts
nalin [4]

Answer:

He has a speed of 16.60m/s after 35.0 meters.

Explanation:

The final velocity can be determined by means of the equations for a Uniformly Accelerated Rectilinear Motion:

v_{f}^{2} = v_{i}^{2} + 2ad        

v_{f} = \sqrt{v_{i}^{2} + 2ad}  (1)

The acceleration can be found by means of Newton's second law:

\sum F_{net} = ma

Where \sum F_{net} is the net force, m is the mass and a is the acceleration.

Fx + Fy = ma  (2)

All the forces can be easily represented in a free body diagram, as it is shown below.

Forces in the x axis:

F_{x} = F - F_{air}  (3)

Forces in the y axis:

F_{y} = 0 (4)

Solving for the forces in the x axis:

F_{x} = F - F_{air}

Where F = 1.150x10^{3} N and F_{air} = 795 N:

F_{x} = 1.150x10^{3} N - 795 N

F_{x} = 355 N

Replacing in equation (2) it is gotten:

Fx + Fy = ma

355 N + 0 N = (90.0 Kg)a

355 N = (90.0 Kg)a

a = \frac{355 N}{90.0Kg}

a = \frac{355 Kg.m/s^{2}}{90.0Kg}

a = 3.94 m/s^{2}

So the acceleration for the cyclist is 3.94 m/s^{2}, now that the acceleration is known, equation (1) can be used:

v_{f} = \sqrt{v_{i}^{2} + 2ad}

However, since he was originally at rest its initial velocity will be zero (v_{i} = 0).

v_{f} = \sqrt{2ad}

v_{f} = \sqrt{2(3.94m/s^{2})(35.0m)}

v_{f} = 16.60m/s

He has a speed of 16.60m/s after 35.0 meters

8 0
3 years ago
А A van accelerates from Amst to zomst in 8s. How far does it<br>travel in<br>this time?​
8_murik_8 [283]

Answer:

1663m

Explanation:

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6 0
3 years ago
PLEASE HELP!
lutik1710 [3]

Answer:

Thats her fault.........................b

Explanation:

6 0
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The formula for speed is v = s/t. <br> a. True<br> b. False
crimeas [40]
If you mean S is the distance then it is true 
Velocity = Distance / time 
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Explain in terms of energy flow how a cold pack works on a sprained ankle
sergij07 [2.7K]
The <span>flow of how a cold pack works on a sprained ankle is based on the second law of thermodynamics which states that energy will flow from a higher to a lower temperature. So your body heat will flow to the cold pack in which you will feel the coldness of the pack.</span>
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