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Allisa [31]
3 years ago
5

12. A 1.2-kg bucket of water is held by a string and spun in a horizontal circle with an acceleration of 24.6

Physics
1 answer:
frozen [14]3 years ago
6 0

Answer:

1.1 m

Explanation:

a = v² / r

24.6 m/s² = (5.2 m/s)² / r

r = 1.1 m

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Steel wire rope is used to lift a heavy object. We use a 3.1m steel wire that
kaheart [24]

Answer:

Young's modulus for the rope material is 20.8 MPa.    

 

Explanation:

The Young's modulus is given by:

E = \frac{FL_{0}}{A\Delta L}

Where:

F: is the force applied on the wire

L₀: is the initial length of the wire = 3.1 m

A: is the cross-section area of the wire

ΔL: is the change in the length = 0.17 m

The cross-section area of the wire is given by the area of a circle:

A = \pi r^{2} = \pi (\frac{0.006 m}{2})^{2} = 2.83 \cdot 10^{-5} m^{2}

Now we need to find the force applied on the wire. Since the wire is lifting an object, the force is equal to the tension of the wire as follows:

F = T_{w} = W_{o}

Where:

T_{w}: is the tension of the wire

W_{o}: is the weigh of the object = mg

m: is the mass of the object = 1700 kg

g: is the acceleration due to gravity = 9.81 m/s²

F = mg = 1700 kg*9.81 m/s^{2} = 16677 N

Hence, the Young's modulus is:

E = \frac{16677 N*0.006 m}{2.83 \cdot 10^{-5} m^{2}*0.17 m} = 20.8 MPa          

Therefore, Young's modulus for the rope material is 20.8 MPa.                

I hope it helps you!                                    

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Answer:

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Answer:

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