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meriva
3 years ago
7

Which statement is a description of boyle's law?The temperature and volume of a gas are directly proportional when pressure is c

onstant.
The temperature and volume of a gas are inversely proportional when pressure is constant.
The volume and pressure of a gas are directly proportional when temperature is constant.
The volume and pressure of a gas are inversely proportional when temperature is constant.
Physics
2 answers:
torisob [31]3 years ago
6 0
P and V are inversely proportional when temperature is constanst.
answer is the last option.


mel-nik [20]3 years ago
4 0

Answer: The correct answer is:

The volume and pressure of a gas are inversely proportional when temperature is constant.

Explanation:

Boyle's Law states that pressure of gas is inversely proportional to the volume of the gas at constant temperature in Kelvins.

P\propto \frac{1}{V}  (At constant temperature)

Where: P = pressure of the gas

V = Volume occupied by the gas

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An electromagnetic wave is traveling through free space. The amplitudes of the wave's electric and magnetic fields are E 0 E0 an
Sauron [17]

Answer:

B = Bo / 2

Explanation:

Magnesium and electric fields are related in an electromagnetic wave

        E / B = c

If the electric field is halved the magnetic field must also be halved to meet the written equation

           B = Bo / 2

5 0
3 years ago
Read 2 more answers
Phosphorus-32, a radioactive isotope of phosphorus-31 (atomic number 15), undergoes a form of radioactive decay whereby a neutro
dimulka [17.4K]

Answer:

The product of the decay its Sulfur-32

Explanation:

Phosphorus-32 ( lets write it _{15}^{32}P, where the number above its the atomic mass and the number below the atomic number) decays turning a neutron into a proton and emitting radiation on the form of a electron. This is the beta minus decay, and, actually, an electronic antineutrino its also produced. We can write this decay for an X isotope with a Y isotope produced as:

_{Z}^{A}X \to _{Z+1}^{A}Y + e^- + \bar{\nu_e}

where e^- its the electron, and \bar{\nu_e} the electronic antineutrino . We can see that the atomic number increases by one (cause a proton it produced and retained into the nucleus), and the atomic mass is approximately the same (there is a small difference between the neutron and proton mass, but its very small).

So, Phosphorus-32 (atomic number 15) will turn to an element with atomic number 16, and atomic mass 32, as:

_{15}^{32}P \to _{15+1}^{32}Y + e^- + \bar{\nu_e}.

_{15}^{32}P \to _{16}^{32}Y + e^- + \bar{\nu_e}.

The Y isotope must have an atomic number of 16 and an atomic mass of 32. The element with atomic number 16 its Sulfur (S), so, our decay its

_{15}^{32}P \to _{16}^{32}S + e^- + \bar{\nu_e}.

and the product of such decay its Sulfur-32

5 0
3 years ago
What are the conditions under which the resultant of three coplanar forces is zero?<br>​
serg [7]
When three or more coplanar forces are acting at a point and the vector diagram closes, there is no resultant. The forces acting at the point are in equilibrium.
4 0
2 years ago
Analyze how buffers allow you to eat acidic and basic foods without changing your blood pH.
blondinia [14]
Buffers neutralize the acid and the bases
7 0
3 years ago
When an object is placed 110 cm from a diverging thin lens, its image is found to be 55 cm from the lens. The lens is removed, a
Kazeer [188]

Explanation:

Given that,

Object distance u= -110 cm

Image distance v= 55 cm

We need to calculate the focal length for diverging lens

Using formula of lens

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

Put the value into the formula

\dfrac{1}{-f}=\dfrac{1}{55}-\dfrac{1}{-110}

\dfrac{1}{f}=-\dfrac{3}{110}

f=-36.6\ cm

The focal length of the diverging lens is 36.6 cm.

Now given a thin lens with same magnitude of focal length 36.6 cm is replaced.    

Here, The object distance is again the same.

We need to calculate the image distance for converging lens

Using formula of lens

\dfrac{1}{36.6}=\dfrac{1}{v}-\dfrac{1}{-110}

Here, focal length is positive for converging lens

\dfrac{1}{v}=\dfrac{1}{36.6}-\dfrac{1}{110}

\dfrac{1}{v}=\dfrac{367}{20130}

v=54.85\ cm

The distance of the image is 54.85 cm from converging lens.

Hence, This is the required solution.

5 0
3 years ago
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