Answer:
B = Bo / 2
Explanation:
Magnesium and electric fields are related in an electromagnetic wave
E / B = c
If the electric field is halved the magnetic field must also be halved to meet the written equation
B = Bo / 2
Answer:
The product of the decay its Sulfur-32
Explanation:
Phosphorus-32 ( lets write it
, where the number above its the atomic mass and the number below the atomic number) decays turning a neutron into a proton and emitting radiation on the form of a electron. This is the beta minus decay, and, actually, an electronic antineutrino its also produced. We can write this decay for an X isotope with a Y isotope produced as:

where
its the electron, and
the electronic antineutrino . We can see that the atomic number increases by one (cause a proton it produced and retained into the nucleus), and the atomic mass is approximately the same (there is a small difference between the neutron and proton mass, but its very small).
So, Phosphorus-32 (atomic number 15) will turn to an element with atomic number 16, and atomic mass 32, as:
.
.
The Y isotope must have an atomic number of 16 and an atomic mass of 32. The element with atomic number 16 its Sulfur (S), so, our decay its
.
and the product of such decay its Sulfur-32
When three or more coplanar forces are acting at a point and the vector diagram closes, there is no resultant. The forces acting at the point are in equilibrium.
Buffers neutralize the acid and the bases
Explanation:
Given that,
Object distance u= -110 cm
Image distance v= 55 cm
We need to calculate the focal length for diverging lens
Using formula of lens

Put the value into the formula


The focal length of the diverging lens is 36.6 cm.
Now given a thin lens with same magnitude of focal length 36.6 cm is replaced.
Here, The object distance is again the same.
We need to calculate the image distance for converging lens
Using formula of lens

Here, focal length is positive for converging lens



The distance of the image is 54.85 cm from converging lens.
Hence, This is the required solution.