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zlopas [31]
3 years ago
9

I WILL MARK YOU AS BRAINLIEST IF RIGHT The fastest pitch ever recorded in MLB was thrown by Aroldis Chapman at 5 points 105.1 mp

h . If the 0.145 kg baseball accelerated 96 m/s / s , how much force did Chapman apply to the ball? Round your answer to the nearest whole number
Physics
1 answer:
Goshia [24]3 years ago
5 0

Answer: The force was 13.92 Newtons.

Explanation:

First, let's recall the second Newton's law:

The net force is equal to the mass times the acceleration, or:

F = m*a

where:

F = force

m = mass

a = acceleration.

When the player hits the ball with the bat, he applies a force that accelerates the ball for a small period of time, that increases greatly the speed of the ball.

In this case, we know that:

the mass of the ball is 0.145 kg

The acceleration of the ball is 96m/s^2

Then we can input those values in the above equation to find the force.

F = 0.145kg*96m/s^2 = 13.92 N

The force was 13.92 Newtons.

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When a parachute opens, the air exerts a large drag force on it. This upward force is initially greater than the weight of the s
skad [1K]

Answer:

The value a = 1.1842 \ m/s^2

Explanation:

From the question we are told that

The weight of the sky diver is W =  968 \  N

The magnitude of the drag force is D_f  =  1085 \  N

The mass of the sky diver is m  =  98.8 \ kg

Generally the net force acting on the sky diver is mathematically represented as

F = m * a  =  D_f  - W

Hence the acceleration of the sky diver is mathematically represented as

a =  \frac{D_f - W}{ m}

=> a =  \frac{1085 - 968}{  98.8}

=> a = 1.1842 \ m/s^2

7 0
3 years ago
Two male moose charge at each other with the same speed and meet on a icy patch of tundra. As they collide, their antlers lock t
Ksenya-84 [330]
Change in velocity of larger moose: (1/3)v - v = -(2/3)v 
<span>change in velocity of small moose: (1/3)v - (-v) = (4/3)v </span>
<span>- (change in velocity of larger moose)/(change in velocity of smaller moose) = 2

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.



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4 0
3 years ago
Read 2 more answers
ListenA bicycle and its rider have a combined mass of 80. kilograms and a speed of 6.0 meters per second. What is the magnitude
Setler [38]

Answer:

a) 1.2\times 10^2\ N

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

a = Acceleration

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{0-6}{4}\\\Rightarrow a=-1.5\ m/s^2

The acceleration of the bicycle and rider is -1.5 m/s²

Force

F=ma\\\Rightarrow F=80\times -1.5\\\Rightarrow F=-120\ N=-1.2\times 10^2\ N

The magnitude of the average force needed to bring the bicycle and its rider to a stop is 1.2\times 10^2\ N

3 0
3 years ago
Antifreeze is a "must have" in an Albertan winter because it helps keep your vehicle engine from freezing in cold temperatures.
Natasha_Volkova [10]

Products such as antifreeze are composed of organic compounds that are classified as <em>alcohols</em>. (a)

Maybe those other classes of chemicals also lower the freezing temperature of water, just like alcohol does.  I don't know.  But alcohol is what's used to make anti-freeze.  I'm guessing alcohol must be cheaper, less toxic, and less corrosive inside the engines' cooling systems than any of that other stuff is.

4 0
3 years ago
How much force must be applied on a blade of length 4cm and thickness of 0.1mm to exert a pressure of 4000000pa?
Viktor [21]

Answer:

F= 403429 kpa

Explanation:

Pressure is the product of force and area

Mathematically,

P=F*A -------where F is force and A is area.

A= 40 *0.1 = 4mm² -----convert to m²

A= 4e⁻⁶ m²

P= 4000000 pa

F= P/A = 4000000/4e⁻⁶

F= 403428793.493 pa

F= 403429 kpa

7 0
3 years ago
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