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umka21 [38]
4 years ago
14

Please help and explain if you can

Mathematics
2 answers:
Keith_Richards [23]4 years ago
7 0

Answer:

I think the answer is 100, but correct me if im wrong

svp [43]4 years ago
3 0
X would be 40 because the angle is inscribed meaning that it’s half the arc since we half 100 and we have half a circle.That means we need the other arc BC to be 80.
Z would be 50 since it’s half the arc which is 100.
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Review the two box and whisker plots:
Ber [7]

Answer:

Male students have a greater median.

Step-by-step explanation:

The median is the bold line (look at the attached image)

The male's median is greater than 60.

The female's median is less than 60.

Hope that helps!

7 0
3 years ago
Don works in home construction. He determined that the function t(A)=144A/9.252 gives the total number of 9 in. tiles needed to
Oksanka [162]

Answer:

6,226 tiles of 9 in are needed to cover an area of 400 square feet

Step-by-step explanation:

Let

A -----> an area in square feet

t(A) ---> the total number of 9 in. tiles needed

we have

t(A)=\frac{144A}{9.252}

For A=400 ft^2

substitute in the equation and solve for t

t(400)=\frac{144(400)}{9.252}

t(400)=6,226\ tiles

That means -----> 6,226 tiles of 9 in are needed to cover an area of 400 square feet

6 0
3 years ago
URGENT 23-28 with work
dybincka [34]
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7 0
3 years ago
The two dot plots below compare the forearm lengths of two groups of schoolchildren:
Angelina_Jolie [31]

Answer:

Group A, because seven children have a forearm length longer than 10 inches

Step-by-step explanation:

Create the dot plots based on the given information (please see attached images).

Group A = blue dots

Group B = red dots

From inspection of the attached dot plots, we can see that Group A appears to have the longer average forearm length.  This is because 7 children have a forearm length of longer than 10 inches.

To calculate the average forearm length, sum all data values and divide by the total number of data values.

\textsf{Average of Group A}=\dfrac{ 3 \times 10 + 4 \times 11 + 3 \times 12}{10}=11

\textsf{Average of Group B}=\dfrac{ 3 \times 9 + 5\times 10+ 2\times 11}{10}=9.9

Thus proving that Group A has the longer average former length.

7 0
2 years ago
Read 2 more answers
I need this math problem done as soon as possible!
Vesna [10]

Answer:

See below

Step-by-step explanation:

<u>Parent function:</u>

  • y = 3ˣ

<u>Transformed function:</u>

  • y = 4(3)⁻²ˣ⁺⁸ + 6, (note. I see this as 8, sorry if different but it doesn't make any change to transformation method)

<u>Transformations to be applied:</u>

  • f(x) → f(-x) reflection over y-axis
  • f(-x) → f(-2x) stretch horizontally by a factor of 2
  • f(-2x) → f(-2x + 8) translate 8 units right
  • f(-2x + 8) → 4f(-2x + 8)  stretch vertically by a factor of 4
  • 4f(-2x + 8) → 4f(-2x + 8) + 6 translate 6 units up
7 0
3 years ago
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