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Alenkasestr [34]
3 years ago
13

Find an equation for the line that passes through the points (-3,-6) and (3,3)

Mathematics
1 answer:
Alecsey [184]3 years ago
6 0
Y=3/2x-1.5 would be the equation
You might be interested in
Bonita deposited 1300 into a bank account that earned 5.75% simple interest each year. She earned $299 in interest before closin
worty [1.4K]

Answer:

For 4 years the money was in the account .

Step-by-step explanation:

Formula

Simple\ interest = \frac{Principle\times Rate\times Time}{100}

As given

Bonita deposited 1300 into a bank account that earned 5.75% simple interest each year.

She earned $299 in interest before closing the account.

Principle = $1300

Rate = 5.75%

Simple interest = $299

Putting all the values in the formula

299 = \frac{1300\times 5.75\times Time}{100}

Time= \frac{299\times 100}{1300\times 5.75}

Time= \frac{29900\times 100}{1300\times 575}

Time= \frac{2990000}{747500}

Time = 4 years

Therefore for 4 years the money was in the account .


8 0
3 years ago
If a polygon has an interior angle of 144, what kind of polygon is it? (find the # of sides first
ikadub [295]
<span>Each Interior Angle = <span>(<span>(Number of Sides -2) • 180 degrees<span>)<span> ÷ (Number of Sides)

Solving for number of sides
</span></span></span></span></span>
<span>Each Interior Angle / 180 = <span>(N -2) <span>/ (N)

144 / 180 = (n-2) / n

144 * n = 180n -360
360 = 36 n

n = 10 the number of sides

Source:
http://www.1728.org/polygon.htm

</span></span></span>
5 0
3 years ago
United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the n
Ivanshal [37]

Answer:

<u><em>a) The probability that exactly 4 flights are on time is equal to 0.0313</em></u>

<u><em></em></u>

<u><em>b) The probability that at most 3 flights are on time is equal to 0.0293</em></u>

<u><em></em></u>

<u><em>c) The probability that at least 8 flights are on time is equal to 0.00586</em></u>

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

<em>United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures. </em>

<em>a) The probability that exactly 4 flights are on time is = </em>

<em>b) The probability that at most 3 flights are on time is = </em>

<em>c)The probability that at least 8 flights are on time is =</em>

<h2>Solution to the problem</h2>

<u><em>a) Probability that exactly 4 flights are on time</em></u>

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

           P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}

Where _nC_x is the number of different combinations of x success in n trials.

            _nC_x=\frac{x!}{n!(n-x)!}

Hence,

            P(X=4)=_9C_4\cdot (0.5)^4\cdot (0.5)^{5}

                                _9C_4=\frac{4!}{9!(9-4)!}=126

            P(X=4)=126\cdot (0.5)^4\cdot (0.5)^{5}=0.03125

<em><u>b) Probability that at most 3 flights are on time</u></em>

The probability that at most 3 flights are on time is equal to the probabiity that exactly 0 or exactly 1 or exactly 2 or exactly 3 are on time:

         P(X\leq 3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)

P(X=0)=(0.5)^9=0.00195313 . . . (the probability that all are not on time)

P(X=1)=_9C_1(0.5)^1(0.5)^8=9(0.5)^1(0.5)^8=0.00390625

P(X=2)=_9C_2(0.5)^2(0.5)^7=36(0.5)^2(0.5)^7=0.0078125

P(X=3)= _9C_3(0.5)^3(0.5)^6=84(0.5)^3(0.5)^6=0.015625

P(X\leq 3)=0.00195313+0.00390625+0.0078125+0.015625=0.02929688\\\\  P(X\leq 3) \approx 0.0293

<em><u>c) Probability that at least 8 flights are on time </u></em>

That at least 8 flights are on time is the same that at most 1 is not on time.

That is, 1 or 0 flights are not on time.

Then, it is easier to change the successful event to not being on time, so I will change the name of the variable to Y.

          P(Y=0)=_0C_9(0.5)^0(0.5)^9=0.00195313\\ \\ P(Y=1)=_1C_9(0.5)^1(0.5)^8=0.0039065\\ \\ P(Y=0)+P(Y=1)=0.00585938\approx 0.00586

6 0
3 years ago
UREGNT -- BRAINLIEST!
Nady [450]

Answer:

12

Step-by-step explanation:

∛1728 = ∛2*2*2*2*2*2*3*3*3*3 = 2*2*3 = 12

3 0
3 years ago
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Which best describes the orthocenter of a triangle?
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B. I guessing let me kno if it’s wrong
8 0
2 years ago
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