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lukranit [14]
2 years ago
7

What is the electric current measured in

Physics
1 answer:
cluponka [151]2 years ago
6 0

An ampere (AM-pir), or amp

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Someone help me please
Maru [420]
H I and u your weclome
8 0
2 years ago
explain y it is easier to loosen a tight but using a spanner with along handle than with a short handle​
8090 [49]

Answer:

This is because using a long handled requires less force to the center of gravity and makes it easier to rotate than a short handled spanner

3 0
3 years ago
What is the momentum of an object that is moving in a straight line at a speed of 10 m/s and has a mass of 10 kilograms?
Aleksandr-060686 [28]
The momentum of an object is given by the product between its mass and its velocity:
p=mv
where m is the mass and v the velocity.

For the object in our problem, m=10 kg and v=10 m/s, therefore its momentum is
p=mv=(10 kg)(10 m/s)=100 kg m/s
So, the correct answer is B).
8 0
3 years ago
What is the difference in Neil Armstrong’s weight on the moon and on earth? Neils mass is 160kg including his spacesuit and back
Len [333]

Explanation:

Given parameters:

Mass of Neil Armstrong = 160kg

Gravitational pull of earth = 10N/kg

Moon's pull = 17% of the earth's pull

Unknown:

Difference between Armstrong's weight on moon and on earth.

Solution:

To find the weight,

   Weight = mass x acceleration due to gravity = mg

Moon's gravitational pull = 17% of the earth's pull = 17% x 10 = 1.7N/kg

Weight on moon = 160 x 1.7 = 272N

Weight on earth = 160 x 10 = 1600N

The difference in weight = 1600 - 272 = 1328N

The weight of Armstrong on earth is 1328N more than on the moon.

Learn more:

Weight and mass brainly.com/question/5956881

#learnwithBrainly

3 0
3 years ago
An electric fan is running on HIGH. After fan has been running for 1.3 minutes, the LOW button is pushed. The fan slows down to
mafiozo [28]

Answer:

    wo = 18.75 rev / s

Explanation:

This is an exercise in endowment kinematics, it indicates that the final angular velocity is w_f = 109 rad / s, the time to reach this velocity is t = 1.87 s and the deceleration a = 4.7 rad / s²

         w_f = w₀ - a t

         w₀ = w_f + a t

         w₀ = 109 + 4.7 1.87

         w₀ = 117.8 rad / s

let's reduce to revolutions / s

         w₀ = 117.8 rad / s (1 rev / 2pi rad)

         w₀ = 18.75 rev / s

8 0
3 years ago
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