Ask question

Ask question

All categories

3 years ago

11

you toss an apple from a tree 5m horizontally. The Apple hits your friend on the ground that is 7m away from the tree. How fast

did you throw the Apple in m/s? hello, answeerr

1 answer:

saw5 [17]3 years ago

8 0

-4.90 seconds -16.8 m/s-

You might be interested in

Which of the following solutions will have the lowest freezing point?

gregori [183]

C. 1.0 mol/kg sodium phosphide (Na3P)<span>

This is because it will produce 4 ions, and thus has the highest molalitiy. (more particles in solution lowers the freezing point)

</span><span>remember if you ever need anything and you dont want to waste points you can just post it on my pfp or message me the question</span>

7 0

4 years ago

What compound makes up carbohydrates?

Aliun [14]

The monomer of glucose makes up all carbohydrates

5 0

3 years ago

For a certain RLC circuit the maximum generator EMF is 125 V and the maximum current is 3.20 A. If le a) the impedance of the ci

MAXImum [283]

Answer:

Part (i)

Z = 39.06 ohm

Part (ii)

R = 21.7 ohm

Explanation:

a) here we know that

maximum value of EMF = 125 V

maximum value of current = 3.20 A

now by ohm's law we can find the impedence as

$z = \frac{V_o}{i_o}$

now we will have

$z = \frac{125}{3.20} = 39.06 ohm$

Part b)

Now we also know that

$\frac{R}{z} = cos\theta$

$\theta = 0.982 rad = 56.3 degree$

now we have

$\frac{R}{39.06} = cos56.3$

$R = 21.7 ohm$

5 0

3 years ago

How much ke is possessed by a 100kg running forward at 4.0 m/s ?

Anvisha [2.4K]

KE = 1/2mv²
= 1/2(100)(4.0²)
KE = 800 J

hope this helps :)

7 0

4 years ago

If a gun is sighted to hit targets that are at the same height as the gun and 95 m away, how low will the bullet hit if aimed di

Elina [12.6K]

Horizontal distance between the bullet and the target (s) = 195 m

Horizontal velocity of the bullet (u) = 275 m/s

Time taken to cover the horizontal distance = $\frac{Distance}{velocity}$

Time taken (t) = $\frac{195}{275}$

t = 0.709 s

Now, in the vertical direction:

Initial velocity (u) = 0 m/s

Let the depth covered be h.

Time taken (T) = 0.709 s

Acceleration due to gravity (g) = 9.8 m/s^2

Now, using the seconds equation of motion:

$h = ut + \frac{1}{2}at^2$

$h = 0 +\frac{1}{2}\times 9.8 \times 0.709^2$

h = 2.463 meters

Hence, the bullet will hit 2.463 meters below the target.

3 0

3 years ago