A 10 inch pizza cost $8 while a 1w inch pizza cost $10.50. Which ilsize is the better deal?

Use braces and digits to designate the set of natural numbers.

alina1380 [7]

Answer:

$N = \{1,2,3,4,5,6,.....\}$

Step-by-step explanation:

Required

Determine the sets of natural number

Represent this set with letter N

From definition of natural numbers, they are integer numbers starting from 1;

In other words: 1,2,3,4,5, and so on.

To represent this as a set of N, we have

$N = \{1,2,3,4,5,6,.....\}$

<em>The ..... means that the counting still continues</em>

6 0

3 years ago

Four more than three times n equals -5

Verizon [17]

3n+4=-5

do the opposite of adding 4. this means you have to subtract 4 from 4. whatever you do to the problem, you must do to the answer. now subtract 4 from -5.

-5-4=-9

since 4-4=0, we can take 4 out of the equation. now you have:

3n=-9

now divide -9 by 3

-9/3=-3

n=-3

hope this helps :)

5 0

3 years ago

A cylinder has a volume of 83 in3 and is 10 in. tall. What is the radius of the cylinder in inches? Round your answer to the nea

Nataly [62]

To find the radius of the cylinder you will use the volume formula and solve for the radius.

V = pi x r^2 x h
83 = 3.14 x r^2 x 10
83 = 31.4 x r^2; divide both sides by 31.4
r^2 = 2.6; find the square root of 2.6
r = 1.6 in.

The radius is approximately 1.6 in.

3 0

2 years ago

ASAP PLEAE HELP I WILL GIVE BRAINEST!<br><br> LOOK AT RHE PICTURE

Mekhanik [1.2K]

Answer:

answer is false

Step-by-step explanation:

4 0

2 years ago

After a long study, tree scientists conclude that a eucalyptus tree will grow at the rate of 0.5 6/ (t+4)3 feet per year, where

kipiarov [429]

Answer:

Step-by-step explanation:

Given the rate at which an eucalyptus tree will grow modelled by the equation 0.5+6/(t+4)³ feet per year, where t is the time (in years).

The amount of growth can be gotten by integrating the given rate equation as shown;

$\int\limits {0.5 + \frac{6}{(t+4)^{3} } } \, dt \\= \int\limits {0.5} \, dt + \int\limits\frac{6}{(t+4)^{3} } } \, dx } \, \\= 0.5t +\int\limits {6u^{-3} } \, du \ where \ u = t+4 \ and\ du = dt\\= 0.5t + 6*\frac{u^{-2} }{-2} + C\\= 0.5t-3u^{-2} +C\\= 0.5t-3(t+4)^{-2} + C$

a) The number of feet that the tree will grow in the second year can be gotten by taking the limit of the integral from t =1 to t = 2

$\int\limits^2_1 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^2_1\\= [0.5(2)-3(2+4)^{-2}] - [0.5(1)-3(1+4)^{-2}]\\= [1-3(6)^{-2}] - [0.5-3(5)^{-2}]\\ = [1-\frac{1}{12}] - [0.5-\frac{3}{25} ]\\= \frac{11}{12}-\frac{1}{2}+\frac{3}{25}\\ = 0.9167 - 0.5 + 0.12\\= 0.5367feet$

b) The number of feet that the tree will grow in the third year can be gotten by taking the limit of the integral from t =2 to t = 3

$\int\limits^3_2 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^3_2\\= [0.5(3)-3(3+4)^{-2}] - [0.5(2)-3(2+4)^{-2}]\\= [1.5-3(7)^{-2}] - [1-3(6)^{-2}]\\ = [1.5-\frac{3}{49}] - [1-\frac{1}{12} ]\\ = 1.439 - 0.9167\\= 0.5223feet$

c) The total number of feet grown during the second year can be gotten by substituting the value of limit from t = 0 to t = 2 into the equation as shown

$\int\limits^2_0 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^2_0\\= [0.5(2)-3(2+4)^{-2}] - [0.5(0)-3(0+4)^{-2}]\\= [1-3(6)^{-2}] - [0-3(4)^{-2}]\\ = [1-\frac{1}{12}] - [-\frac{3}{16} ]\\= \frac{11}{12}+\frac{3}{16}\\ = 0.9167 - 0.1875\\= 0.7292feet$

8 0

2 years ago