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Levart [38]
3 years ago
15

A circle has a central angle measuring 90° that intersects an arc of length 117.75 inches.

Mathematics
2 answers:
olga_2 [115]3 years ago
7 0

Answer:

Radius = 75 inches .

Step-by-step explanation:

Given  : A circle has a central angle measuring 90° that intersects an arc of length 117.75 inches.

To find :  what is the length of the radius of the circle.

Solution : We have given

Central angle = 90°

Arc of length   = 117.75 inches.

Arc length = \frac{theta}{360}* 2 \pi * radius.

Plug the values

Theta = 90 , pi = 3.14 ,  arc length = 117.75 .

117 .75 =  \frac{90}{360}* 2(3.14 ) * radius.

117 .75 =  \frac{1}{4}* 2(3.14 ) * radius

On multiplying both sides 4

117.75 * 4 = 2 * 3.14 * radius .

471 = 6 .28 * radius .

On dividing both sides by 6.28

radius = \frac{471}{6.28}.

Radius = 75 inches .

Therefore, Radius = 75 inches .

pychu [463]3 years ago
5 0
90 degrees is one quarter of a circle so,
circumference = 4 * 117.75 = 471
circumference = 2 * PI * radius
radius = 471 / (2*PI)
radius = <span> <span> <span> 74.9619781963 </span> </span> </span>


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Step-by-step explanation:

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Answer:

Part 1) The shape is a trapezoid

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Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

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see the attached figure

step 2

Find the perimeter

we know that

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P=AB+BC+CD+AD

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d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

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we have

A(-28,2),B(-21,-22)

substitute in the formula

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