No. The area doesn't tell you the dimensions, and you need
the dimensions if you want the perimeter.
If you know the area, you only know the <em><u>product</u></em> of the length and width,
but you don't know what either of them is.
In fact, you can draw an infinite number of <em><u>different</u></em> rectangles
that all have the <em>same</em> area but <em><u>different</u></em> perimeters.
Here. Look at this.
I tell you that a rectangle's area is 256. What is its perimeter ?
-- If the rectangle is 16 by 16, then its perimeter is 64 .
-- If the rectangle is 8 by 32, then its perimeter is 80 .
-- If the rectangle is 4 by 64, then its perimeter is 136 .
-- If the rectangle is 2 by 128, then its perimeter is 260 .
-- If the rectangle is 1 by 256, then its perimeter is 514 .
-- If the rectangle is 0.01 by 25,600 then its perimeter is 51,200.02
72 square centimeters because
<span>(12×10)−(8×6)</span>
<span>120−48</span>
<span>72</span>
The answer for this problem would be -52 because when you do 58-6 it give you 52 so i tried -52+58 and what did it give me 6 so -52 is your answer hope that this helps and here is a tip: negative is the only way to go down in addtion just to let you know <span />
Answer: D
You get the same answer from doing both!
Hmm
2 times 4=8
3 times 8 is not 27
1 times 1=1
2 times 4=8
3 times 9=27
aka
1 times 1^2=1
2 times 2^2=8
3 times 3^2=27
x times x^2=x^3
the rule is y=x^3
