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Vlada [557]
3 years ago
12

What is the scale factor in the dilation?​

Mathematics
1 answer:
BigorU [14]3 years ago
3 0
<h3>Answer: Choice D) 2 & 1/2</h3>

Work Shown:

Length of AC = 10-4 = 6 units (I'm subtracting the x coordinates)

Length of A'C' = 25-10 = 15 units

Scale factor = (A'C')/(AC) = 15/6 = 5/2 = 2.5 = 2 & 1/2

Triangle A'B'C' has side lengths that are 2 & 1/2 times longer compared to the corresponding sides of triangle ABC.

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What is the 10th term in the pattern with the formula 5n+100?
postnew [5]
Jusst plug in n = 10

so its 5(10) + 100  =  150
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Step-by-step explanation:

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2 years ago
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Q6. (15 points) IQ examination scores of 500 members of a club are normally distributed with mean of 165 and SD of 15.
melamori03 [73]

Answer:

a) 0.8413

b) 421

c) P_{95} = 189.675

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 165

Standard Deviation, σ = 15

We are given that the distribution of  IQ examination scores is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(IQ scores at most 180)

P(x < 180)

P( x < 180) = P( z < \displaystyle\frac{180 - 165}{15}) = P(z < 1)

Calculation the value from standard normal z table, we have,  

P(x < 180) = 0.8413 = 84.13\%

b) Number of the members of the club have IQ scores at most 180

n = 500

\text{Members} = n\times \text{P(IQ scores at most 180)}\\= 500\times 0.8413\\=420.65 \approc 421

c) P(X< x) = 0.95

We have to find the value of x such that the probability is 0.95

P( X < x) = P( z < \displaystyle\frac{x - 165}{15})=0.95  

Calculation the value from standard normal z table, we have,  

P(z < 1.645) = 0.95

\displaystyle\frac{x - 165}{15} = 1.645\\\\x = 189.675  

P_{95} = 189.675

8 0
3 years ago
I need help please explain your work for number 7 only
Keith_Richards [23]

Answer:

Transitive property

Step-by-step explanation:

When a=c and b=c, a=b

A would be 16+43

B would be 59

C would be 10+49

5 0
2 years ago
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