Work Shown:
Length of AC = 10-4 = 6 units (I'm subtracting the x coordinates)
Length of A'C' = 25-10 = 15 units
Scale factor = (A'C')/(AC) = 15/6 = 5/2 = 2.5 = 2 & 1/2
Triangle A'B'C' has side lengths that are 2 & 1/2 times longer compared to the corresponding sides of triangle ABC.
Answer:
2/3
Step-by-step explanation:
x^2 = 4/9
x = 2/3
f(x) = 1/4x + 25
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