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Annette [7]
3 years ago
8

Detached earlobes are dominant a child inherits genes with the genotype we. What is a chance that they would likely have detache

d earlobes 0% 25% 50% 75%
Chemistry
2 answers:
Ipatiy [6.2K]3 years ago
8 0
75% is the chance that they will have detached earlobes
krok68 [10]3 years ago
4 0
It would be a 75% chance for the child to have a detached earlobe.
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Which organic prefix is matched with the number of carbon atoms that it represents?
Mandarinka [93]

Answer:heat-,7

Explanation:According to table P, heat- is an organic prefix used to represent 7 carbon atoms

8 0
3 years ago
What is the molar mass, in grams, of a mole of an element equal to?
insens350 [35]

Answer:

B. the atomic weight of the element

Explanation:

since it talks about mass i think weight

5 0
3 years ago
-- A scientist combines 14 grams of potassium nitrate with an unknown amount of
igor_vitrenko [27]

Answer:

The unknown amount of potassium chloride is 13.6 grams.            

 

Explanation:

The reaction of 14 grams of KNO₃ with KCl produces a total mass of 27.6 grams of the products.

The law of conservation of mass tells us that the total mass of the reactants must be the same that the total mass of the products. So, we can find the mass of KCl as follows:

m_{r} = m_{p}

Where <em>r</em> is for reactants and <em>p </em>is for products

m_{KNO_{3}} + m_{KCl} = m_{p}

14 g + m_{KCl} = 27.6 g

m_{KCl} = 27.6 g - 14 g = 13.6 g

Therefore, the unknown amount of potassium chloride is 13.6 grams.           

I hope it helps you!

5 0
3 years ago
A container of carbon dioxide has a volume of 240 mL at a temperature of 22°C. If the pressure remains constant, what is the vol
astraxan [27]

Answer:

Volume of the CO_{2} gas at 44°C is <u>258 ml.</u>

Explanation

here,

using Charles' law ,

\frac{V}{T} =\frac{v}{t}

where , V= initial volume          v= final volume

             T=initial temperature    t = final temperature

Given - pressure is constant ,

so , putting the values -

V= 240ml

T= 22 + 273K = 295K                      (since converting celsius into kelvin that

                                                         is +273K )

v =?

t = 44+ 273K = 317K

Now , putting the given values in charles' law ,

\frac{240ml}{295K} =\frac{v}{317K}

240ml x317K = v x 295K     (through cross multiplication )

v =\frac{240ml\times317K}{295K}

= 258ml .

thus ,<u> the volume of carbon dioxide in a container at 44°C IS 258ml .</u>

7 0
3 years ago
You are a NASCAR pit crew member. Your employer is leading the race with 20 laps to go. He just finished a pit stop and has 5.0
jek_recluse [69]

Answer:

Since there are 3500 g of fuel left in the tank, and he needs only 1687.5 g to complete 20 laps, he has enough fuel to complete the race. I will tell the driver that he does not need to make another pit stop as he has enough fuel to complete the race.

Explanation:

Density = mass / volume

Density of fuel = 700 g/ 1 gal

Therefore, the mass of fuel in 1 gallon = 700 g

The driver has 5.0 gallons of fuel in the tank.

The mass of 5.0 gallons of fuel = 5 × 700 = 3500 g of fuel

Equation of the combustion of fuel, C₅H₁₂ is given below:

C₅H₁₂ + 8 O₂ ---> 6 H₂O + 5 CO₂

1 mole C₅H₁₂ requires 8 moles of O₂

1 mole of C₅H₁₂ has a mass = 72 g

8 moles of O₂ has a mass = 256 g

Therefore, 300 g of O₂ will require 300 × (72/256) g of C₅H₁₂ = 84.375 g of C₅H₁₂

84.375 g of fuel is used by the car per lap;

20 laps will require 20 × 84.375 g of fuel = 1687.5 g of fuel.

Since there are 3500 g of fuel left in the tank, and he needs only 1687.5 g to complete 20 laps, he has enough fuel to complete the race. I will tell the driver that he does not need to make another pit stop as he has enough fuel to complete the race.

7 0
3 years ago
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