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igomit [66]
3 years ago
12

A container of carbon dioxide has a volume of 240 mL at a temperature of 22°C. If the pressure remains constant, what is the vol

ume at 44°C?​
Chemistry
1 answer:
astraxan [27]3 years ago
7 0

Answer:

Volume of the CO_{2} gas at 44°C is <u>258 ml.</u>

Explanation

here,

using Charles' law ,

\frac{V}{T} =\frac{v}{t}

where , V= initial volume          v= final volume

             T=initial temperature    t = final temperature

Given - pressure is constant ,

so , putting the values -

V= 240ml

T= 22 + 273K = 295K                      (since converting celsius into kelvin that

                                                         is +273K )

v =?

t = 44+ 273K = 317K

Now , putting the given values in charles' law ,

\frac{240ml}{295K} =\frac{v}{317K}

240ml x317K = v x 295K     (through cross multiplication )

v =\frac{240ml\times317K}{295K}

= 258ml .

thus ,<u> the volume of carbon dioxide in a container at 44°C IS 258ml .</u>

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What is the main difference between protons and neutrons?
Lorico [155]

Answer:

Protons have a much larger volume than neutrons.

Explanation:

Protons have a slightly smaller mass than neutrons.

Protons have a positive charge.

Protons and neutrons make up the nucleus.

8 0
3 years ago
A CaCl2 solution is given to increase blood levels of calcium. If a patient receives 6.1 mL of a 12 % (m/v) CaCl2 solution, how
Yuliya22 [10]

Mass of CaCl₂ = 0.732 g

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

\tt \%(m/v)\rightarrow 12\%=\dfrac{mass~CaCl_2}{volume~of~solution}\times 100\%\\\\mass~CaCl_2=12\%\times 6.1\div 100\%\\\\mass~CaCl_2=0.732~g

5 0
3 years ago
More help please!?!?!?!?!
e-lub [12.9K]
It's back wards lol you need to take it right
6 0
3 years ago
Read 2 more answers
The three naturally occurring isotopes of potassium are 39K, 38.963707u; 40K, 39.963999u; and 41K.The percent natural abundances
sweet-ann [11.9K]

Answer:

The isotopic mass of 41K is 40.9574 amu

Explanation:

Step 1: Data given

The isotopes are:  

39K with an isotopic mass of 38.963707u and natural abundance of 93.2581%

40K with an isotopic mass of 39.963999u

41K wit natural abundance of 6.7302 %

Average atomic mass =39.098 amu  

Step 2: Calculate natural abundance of 40 K

100 % - 93.2581 % - 6.7302 %

100 % = 0.0117 %

Step 3: Calculate isotopic mass of 41K

39.098 = 38.963707 * 0.932581 + 39.963999 * 0.000117 + X * 0.067302

39.098 = 36.33681 + 0.0046758 +  X * 2.067302

X = 40.9574 amu

The isotopic mass of 41K is 40.9574 amu

8 0
3 years ago
PH is 7.45. Calculate value of [H3O+] and [OH-]
lana66690 [7]

Answer:

The answer is (H30+) =3,55e-8M and (OH-)=2,82e-7M

Explanation:

We use the formulas:

pH= - log(H30+)  and Kwater=(H30+)x(OH-)

pH= - log(H30+)  ----< (H30+)= antilog- pH=antilog- 7,45=3,55E-8M

Kwater=(H30+)x(OH-)

(OH-)=Kwater/(H30+)= 1,00e-14/3,55e-8 = 2,82e-7

8 0
3 years ago
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